Page 11 - Focus SPM KSSM 2021 Tingkatan 5 - Maths DLP

Mathematics Form 5 Chapter 2 Matrices

– 2
(b) 5 3 –1 2 4 3 4 –6 4 SPM Highlights
–2 3
–5
8
– 2
+ 3
–8 7
= 3 –5 10 4 3 8 –12 4 3 11 7 4 3 4 2 4 3 3 –1 4 =
10 –9
5
4
–
–10 16
–10 15
A 3 18 8 4 C 3 17 15 4
6
–20 –2
3
= 3 –5 – 8 10 – (–12) 4 B 3 12 8 4 D 3 17 15 4
15 – 16
–10 – (–10)
6
= 3 –13 22 4 Solution 3 –22 2
0
–1
3 11 7 4 3 4 2 4 3 3 –1 4 Chapter 2
– 2
+ 3
4
–8 7
5
10 –9
14 11 7 12 6 6 –2
–
+
= 3 10 –9 4 3 –24 21 4 3 8 10 4
Chapter 2
1
It is given that M − [9 –1] + 3[2 7] = 4[5 8]. 17 15
2 = 3 4
Find matrix M. –22 2
Answer: D
Solution
1 M − [9 –1] + 3[2 7] = 4[5 8] Example of HOTS
HOTS Question
2
1 M = 4[5 8] + [9 –1] – 3[2 7] Mr Yusof has two vegetable stalls, A and B, in a
2 market. The table below shows the sales of cabbage
= [20 32] + [9 –1] – [6 21] and carrot at his stalls.
= [20 + 9 – 6 32 – 1 – 21] Stall
M = 2[23 10] Vegetable A B
= [46 20]
Cabbage 60 92
Carrot 56 75
15 It is given that the sales of cabbage and carrot at
stall A need to be halved. Calculate the total sales of
3x
x
–20
=
Given that 3 4 3 4 3 4 , find the value of x cabbage and the total sales of carrot by using matrix
+ 2
method.
y
–5
9
and of y. Solution:
1 60 92 122
3 4 3 4 3
Solution 2 56 + 75 = 103 4
x
–20
3x
3 4 3 4 3 4 The total sales of cabbage and carrot are 122 and
+ 2
=
103 respectively.
–5
y
9
Try this HOTS Question
–20
3 3x + 2x 4 3 4 The table below shows Ali’s and Hamid’s expenses
=
9
–5 + 2y
in January.
Compare the corresponding elements: Expense Ali Hamid
3x + 2x = –20 Food
5x = –20 RM200 RM150
x = –4 Entertainment RM50 RM70
It is given that Ali’s expense is not change while
–5 + 2y = 9 Hamid’s expense is doubled in February. Calculate
2y = 14 the difference between Ali’s and Hamid’s expenses
y = 7 in February by using matrix method.
Try Questions 5 – 10 in Try This! 2.2 Answer: 3 100 4
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02 Focus Math F5_E2021.indd 23 18/02/2021 2:32 PM