Page 12 - Focus SPM KSSM 2021 Tingkatan 5 - Maths DLP
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Mathematics  Form 5  Chapter 2  Matrices

                                                                    –1
          C   Multiplying two matrices                  (b)   3 10  3 43 4
                                                                     6
                                                             –4  7
          1.  To multiply two matrices, A and B, the number      Order:  2 ×  2    2  × 1
            of columns in matrix A must be the same as the
            number of rows in matrix B, which is                       Same
                       A    ×    B   =    AB                Hence, the pair of matrices can be multiplied
            Order:   m ×  n   n  ×  p   m × p               and the order of the product is 2 × 1.
                                                                       5
                                                                     3 4
                  Number of   =  Number of              (c)  [12  4  7] 0                                                                                                                                             Chapter  2
                  columns in A   rows in B                             9

                   The order of AB is m × p                 Order:  1 ×  3    3  × 1
   Chapter  2
          2.  In multiplication of two matrices, each element          Same
            in the rows of the first matrix is multiplied by      Hence, the pair of matrices can be multiplied
            corresponding element in the columns of the     and the order of the product is 1 × 1.
 Minion Pro 10pt =  1  second matrix. Then, sum up the results of   –2
 2          multiplication of these elements.           (d)   3 4 [6  1]
                                                              3
                       p
            (a)   [a  b] 3 4  = [ap + bq]                   Order:  2 ×  1    1  × 2
 1                     q
 Arial 8.5 pt =
 2                1 × 2  2 × 1   1 × 1                                 Same
                                                            Hence, the pair of matrices can be multiplied
            (b)   3 a  b 43 p  q s 4 3 ap + br  aq + bs 4      and the order of the product is 2 × 2.
                              =
                  c  d
                                cp + dr  cq + ds
                        r
                  2 × 2   2 × 2      2 × 2                        17
                                                        Find the product of each of the following.
                  a  b
                3 4 q 3              4                       5
                               ap + bq
                         p
            (c)    c  d  3 4  =  cp + dp                (a)   3 4 [1  2]
                  e   f        ep + fq                       –4
                                                                      43
                  3 × 2   2 × 1   3 × 1                       8  –1  6  0
                                                                        1
                                                        (b)   3  2   3  –2 4
                   16                                               9   4
        Determine whether the following pairs of matrices   (c)  [3  –4] 3 4
                                                                   12
        can be multiplied. If yes, state the order of the    Solution
        product.                                             5
             7
                                          –1
                                                             –4
        (a)   3 43 9   11 4      (b)   3 10  3 43 4       (a)   3 4 [1  2]
                                           6
                                   –4  7
                 0   8
             2
                                                            = 3  5 × 1   5 × 2 4
                                                              –4 × 1  –4 × 2
                     3 4           –2
                       5
        (c)  [12  4  7] 0      (d)   3 4 [6  1]             = 3   5  10 4
                       9            3                         –4  –8
        Solution                                              8  –1  6 43 0
                                                                        1
             7
        (a)   3 43 9   11 4                             (b)   3  2   3  –2 4
                                                                        4
                 0   8
             2
            Order:  2 ×  1    2  × 2                        = 3  (8 × 0) + (–1 × 1) + (6 × 4) 4
                                                               (2 × 0) + (3 × 1) + (–2 × 4)
                     Not the same                           = 3 0 – 1 + 24 4
                                                               0 + 3 – 8
            Hence, the pair of matrices cannot be multiplied.  23
                                                            = 3 4
                                                              –5
           24

   02 Focus Math F5_E2021.indd   24                                                             18/02/2021   2:32 PM
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