Page 23 - Focus SPM KSSM 2021 Tingkatan 5 - Maths DLP
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ANSWERS





           Chapter                                            Try This!                        1.2
             1    Variation                                 1.  (a)  The time taken is decreased.
                                                             (b)  The time taken is doubled.
              Try This!                        1.1          2.  The value of xy is not a constant, thus y does not vary inversely
            1.  (a)  The price of the durian is reduced by 20%.  as x.
                                                                                                 2
                                                                      2
             (b)  The price of the durian is doubled.          The value of x y is a constant, thus y varies inversely as x , that
                      y                                      is y ∝   1 2 .
            2.  The value of   is not a constant, thus y does not vary directly   x
                      x
             as x.                                          3.
                       y                                               y
               The value of    is a constant, thus y varies directly as √x, that
                      √x
             is y ∝ √x.                                              60
            3.                                                       50
                        V
                                                                     40
                       6
                                                                     30
                       5
                                                                     20
                       4
                                                                     10
                       3                                                                   1 –
                                                                      O                    x
                       2                                                 0.1 0.2 0.3 0.4 0.5  0.6
                       1                                                     1
                                                               The graph  of  y against   x  is a straight line  starting from the
                       O  10  20  30  40  50  60  A          origin. Hence, y varies inversely as x.
                                                            4.  (a)  f =   4
               The graph of V against A is a straight line passing through the   3 √g
             origin. Hence, V varies directly as A.               128
                                                             (b)  f =    2
            4.  (a)  p = 1.5q                                      g
                      2
                     3
             (b)  p = 48√q                                  5.  (a)  1.024
            5.  d = 25t                                      (b)  0.4
            6.  (a)  283.5                                  6.  (a)  y =   1
             (b)  1.4                                             4x 2
                                                             (b)  2.5
                     3
            7.  (a)  A = 25√B
             (b)  512                                       7.  (a)  G =   45
                                                                   √H
            8.  (a)  m ∝ pq                                  (b)  3.75
             (b)  G ∝ E F
                    2
             (c)  V ∝ r h                                   8.  (a)  T =  540
                    2
                                                                   N
                   2
            9.  (a)  y =  xz   2                             (b)  104
                   3
             (b)  0.9                                       9.  25
           10.  (a)  18
             (b)  1.8                                      10.  2
           11.  x = 121.5, y = 0.6
                                                              Try This!                        1.3
           12.  (a)  E = 9.5MH
             (b)  57                                        1.  (a)  e ∝   1
                                                                   f√g
           13.  (a)  I = 0.04pt                                    Y
             (b)  Mr Kamal can reduce  the term of loan.  To maintain  the        (b)  X ∝
                                                                   Z
                                                                   2
                interest charged, the term of loan is reduced so that  the
                amount of loan is increased.                   (c)  p ∝   q
                                                                   3 √r
                                                                                               161




   11 ANS Focus KSSM Math F5_E2021.indd   161                                                   18/02/2021   3:15 PM
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