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Chemistry Term 3  STPM  Chapter 14 Introduction to Organic Chemistry
                   Secondly, determine the mole ratio of C : H : O
                   C : H : O  =  3.6  : 0.8 :  1.6          Exam Tips
                              12      16                    Exam Tips
                            = 0.3 : 0.8 : 0.1               First, determine the mass of
                            = 3 : 8 : 1                     C, H and O in 6.0 g of Y.
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                   Empirical formula of Y is  C 3 H 8 O.



                   Section C    Essay Questions

                Question 4
                  An organic compound, X, has the following composition by mass:

                                 C, 35.0%;  H, 6.6%;  Br, 58.4%
                  When 1.36 g of X is vaporised, it occupies a volume of 389.2 cm  at 200°C and
                                                                     3
                  101 kPa.
                  (a)  Determine the empirical and molecular formula of X.
                  (b)  Draw and name all possible isomers for X and determine which of them
                      (if any) is/are chiral.


                Answer:
                   (a)  C : H : Br =   35  : 6.6 :  58.4
                                  12       80
                                = 2.9 : 6.6 : 0.73
                                = 4 : 9 : 1
                       Empirical formula of X is C 4 H 9 Br.

                       Using pV = nRT,
                         (101 × 10 )(389.2 × 10 ) = n × 8.31 × (200 + 273)
                               3
                                         –6
                                          n  = 0.010
                                                                 Common Errors
                       Relative molecular mass of X =   1.36  When using the equation
                                                 0.010        pV = nRT, students
                                               = 136          forget to convert the
                                                              temperature from °C to
                                                                              3
                       Let the molecular formula of X be (C 4 H 9 Br) n  ,  K, volume from cm  to
                                                                3
                       [(12 x 4) + 9 + 80]n = 136             m  and pressure from     Term
                                                              kPa to Pa.
                                   136n = 136
                                      n = 1                                           3
                       The molecular formula of X is C 4 H 9 Br.



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