Page 12 - Steady Mate Tg1 - Book A

Matematik Tingkatan 1 Bab 1 Nombor Nisbah

KANDUNGAN
Praktis Berfomat PT3

1. Antara pengiraan berikut, yang manakah memberi nilai Jawapan / Answer:
–14? (i) –4
Which of the following computations gives a value of –14? (ii) 32
A 2 × (–3) – 12 C 30 ÷ (–6) + 9 (iii) 2
B 40 + (–4) × 4 D –8 + (–18) ÷ 3
(b) Berikut adalah satu pola nombor.
The following is a number pattern.
2. Tanda yang manakah akan menjadikan operasi yang

berikut benar? 7, 3, –1, x, –9, y
Which signs would make the following operation correct?
Cari nilai bagi x × 3 – y.
–9 3 = –15 + (–6) 2 Find the value of x × 3 – y.
[4 markah / 4 marks]
A +, + C ×, × Jawapan / Answer:
B –, – D ÷, ÷ x = –5
y = –13
x × 3 – y = –5 × 3 – (–13)
3. (a) Tandakan (✓) bagi hukum operasi yang betul dan
(✗) bagi hukum operasi yang salah. = –15 + 13
Mark (✓) for the correct arithmetic operation law and = –2
(✗) for the incorrect arithmetic operation law.
[2 markah / 2 marks]
(c) Pada suatu hari di gurun Sahara, suhu pada pukul
Jawapan / Answer:
10:00 a.m. dan suhu pada pukul 7:00 p.m. masing-
8 × 207 = 8 × (200 – 7) ✗ masing ialah 58°C di atas sifar dan 5°C di bawah
sifar. Hitung perubahan suhu dalam satu jam di
529 + 284 + 716 = 529 + (284 + 716) ✓ gurun Sahara pada hari tersebut jika penurunan
suhunya adalah sama pada setiap satu jam.
On one day at Sahara desert, the temperature at 10:00
(b) Isi setiap petak dengan nombor yang betul
a.m. and the temperature at 7:00 p.m. are 58°C above
supaya mendapat nilai dalam bulatan seperti yang
zero and 5°C below zero respectively. Calculate the
ditunjukkan dalam rajah berikut. temperature change in one hour at Sahara desert on
Fill in the correct answer in each box in order to obtain that day if the drop in its temperature is the same every
the value in the circle as shown in the diagram. hour.
[2 markah / 2 marks] [3 markah / 3 marks]
Jawapan / Answer: Jawapan / Answer:
Perubahan suhu / Temperature change
24 – 10 – (–34) 48 –3 × (–10 – 6) = +58 – (–5)
= 58 + 5
= 63°C
4. (a) Nilaikan: Tempoh masa / Time interval
Evaluate: = 9 jam / hours 1000 → 1900 = 9 jam/ hours
(i) –8 – (–4) [1 markah / 1 mark]
(ii) –8 × (–4) [1 markah / 1 mark] Perubahan suhu dalam satu jam
(iii) –8 ÷ (–4) [1 markah / 1 mark] Temperature change in one hour
= 63 ÷ 9
= 7°C

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