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Additional Mathematics SPM  Chapter 2  Quadratic Functions


   2.1    Quadratic Equations and                 Solution 2                  Express the
                                                  (a)
                                                         x  + 6x – 2 = 0
          Inequalities                                      x  + 6x = 2       equation in the
                                                                              form of ax  + bx + c
                                                             2
                                                                                     2
                                                               6
                                                                        6
    A    Solving quadratic equations using the        x  + 6x +    2  = 2 +    2   with a = 1.
                                                       2
         method of completing the square and                   2        2
         using the quadratic formula                     x  + 6x + 3  = 2 + 9  Add  b  2  on
                                                         2
                                                                 2
                                                                                  
                                                                                  2a
                                                            (x + 3)  = 11     both sides of the
                                                                 2
     1.  Certain quadratic equations can be solved by         x + 3 = ±  11  equation.
       factorisation.                                            x = –3 ±  11
       For example:  x  + x – 2  = 0                               = –3 +  11  or  –3 –  11
                   2
               (x – 1)(x + 2)  = 0                                 = 0.3166  or  –6.3166
          x – 1 = 0  or  x + 2 = 0
             x = 1          x  = –2                                SPM Tips
 Form 4
     2.  Quadratic equations such as x  = 16, (x – 2)  = 6   Use the calculator to check your answer by
                               2
                                          2
       can be solved easily because the left hand side of   substituting the answer into the quadratic equation
       the equation is a complete square.          involved.
       For example: (x – 2)  = 6
                       2
                                                                                     2
                           
                    x – 2 = ±  6                  (b)  For the case when the coefficient of x   is not 1,
                             
                       x = 2 ±  6                     change the coefficient to 1 by dividing each term in
                             
                                       
                        = 2 +  6  or  2 –  6          the equation by that coefficient before completing
                        = 4.449   or  –0.4495         the square.
                           [to 4 significant figures]   2x  + 4x – 1 = 0
                                                          2
                                                      2
                                                                1
                                                            4
                                                         2
                                                                            by the coefficient
     3.  For quadratic equations that are difficult to     x  +  x –   = 0   Divide each term
                                                      2
                                                                2
                                                            2
                                                                              2
       factorise or cannot be factorised easily such as             1       of x .
                                                             2
       x  + 6x – 2 = 0 and 2x  + 4x – 1 = 0, these equations      x  + 2x =
                       2
        2
                                                                    2
       can be solved using the                                 2  2  1   2  2
                                                       2
       (a)  completing the square method,              x  + 2x +      =   +   
                                                               2
                                                                         2
                                                                    2
                                      
                                  –b ±  b  – 4ac                    1
                                        2
       (b)  quadratic formula method,        .           x  + 2x + 1 =   + 1
                                                          2
                                      2a                            2
                                                                    3
                                                            (x + 1)  =  2
                                                                 2
                          Derivation of the                            3
                          Quadratic Formula                   x + 1 = ±
                                                                       2
                   INFO                                          x = –1 ± 1.2247
     4.  It is easier to use the quadratic formula method         = 0.2247   or  –2.2247
       to solve the quadratic equation ax  + bx + c = 0
                                   2
       when the value of a, b and c are known.        Try Question 1 in ‘Try This! 2.1’
              1
   Determine the roots for each of the following quadratic   2
   equations by using the completing the square.
   (a)  x  – 2 + 6x = 0                           Solve each of the following quadratic equations by
       2
                                                  using the quadratic formula method.
   (b)  2x  + 4x – 1 = 0                          (a)  3x  = 2x + 5
        2
                                                        2
                                                  (b)  6 – 2x = 5x 2
      30
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