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Additional Mathematics SPM  Chapter 2  Quadratic Functions

     (c)  2x  – 5x + 2 . 0                              Example of HOTS
          2
                                                                   HOTS Question
         Table method
           2x  – 5x + 2 = 0                                            6.6 m
             2
          (2x – 1)(x – 2) = 0                                x m
      Factorise the
       quadratic   x   1  x =  1 1   x  2  x = 2 x . 2        x m               4.8 m
       equation     2     2 2
        (2x – 1)   –     0      +       +    +
        (x – 2)    –     –      –       0    +        The diagram above shows a rectangular piece of
     (2x – 1)(x – 2)  +  0      –       0    +        land with a length of 6.6 m and a width of 4.8 m.
                                                      Amin wants to lay square tiles with side x m around
         From the table, it shows that (2x – 1)(x – 2) . 0   the  land  to  build  a  walkway.  If  the  area  of  the                   Form 4
                                                                                       2
                 1                                    region where the tiles are laid is 12.24 m , find the
         when x    or x . 2.                         value of x.
                 2
         Try Question 18  in ‘Try This! 2.1’          Solution
                                                      Area of the region where the tiles are laid
                                                      = 2 × 6.6 × x + 2 × (4.8 – 2x) × x
                8                                     = 13.2x +  9.6x – 4x 2
                                                      = 22.8x – 4x 2
     Find the range of values of x for (2x – 1)(x + 4) < 4 + x.
                                                                        2
                                                      Hence,    22.8x – 4x  = 12.24
     Solution                                             4x  – 22.8x + 12.24 = 0
                                                           2
         (2x – 1)(x + 4)  < 4 + x                      400x  – 2 280x + 1 224 = 0
                                                          2
        2x  + 8x – x – 4  < 4 + x                          50x  – 285x + 153 = 0
                                                             2
          2
       2
      2x  + 7x – 4 – 4 – x  < 0                           –(–285) ± 
                                                                        2
           2x  + 6x – 8  < 0                          x  =         (–285)  – 4(50)(153)
             2
            x  + 3x – 4  < 0                              285 ± 225  2(50)
             2
     a = 1 . 0 ⇒ the shape of the graph is  .           =    100
     When      x  + 3x – 4 = 0                        x  =   510      or  x =   60
                2
            (x – 1)(x + 4) = 0                            100         100
      x – 1  = 0   or   x + 4 = 0                     x  = 5.1    or   x = 0.6
        x  = 1   or    x = –4
     The graph intersects the x-axis at x = 1 and x = –4  5.1 m is longer than the width of the land which is
                                                      4.8 m. So, x = 5.1 is unacceptable.
                                                      Therefore, x = 0.6
                                    x
                   –4         1
                                                       Try this HOTS question
     Therefore, the range of values of x is –4 < x < 1.  The profit made by a factory that is producing
                                                       nuts in packets is given by
                                                              2
                      SPM Tips                         P(t) = 40t  – 7t – 5 676, where t is the time, in
                                                       hours, the production process is running. Find
      Eliminating the common expression of (x + 4) in the   the time of production needed for the factory to
      inequality will cause the range of values of x obtained   get back its capital.
      incomplete.                                      Answer: The time of production must be at least
                 (2x – 1)(x + 4) < (4 + x)             12 hours.
                      2x – 1 < 1
                         2x < 1 + 1
                          x < 1
                                                        Try Questions 20 – 21 in ‘Try This! 2.1’
         Try Question 19  in ‘Try This! 2.1’


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