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 Mathematics  Form 3  Chapter 6 Angles and Tangents of Circles     Mathematics  Form 3  Chapter 7  Plan and Elevations
 Section C    2.  (a)  ∠MOL = 38° × 2  CHAPTER
 = 76°            7       Plans and Elevations
   1.  (a)  (i)  ON = (5 – 1) cm      x = 180° – 90° – 76°  Pelan dan Dongakan
              = 4 cm     x = 14°
    y = 180° – 76°
 2
        NB = 5  – 4 2
    = 3 cm       y = 104°
       1.   View from               Orthogonal
 2
 2
        BD = 3  + 9    (b)  x = ∠LKM × 2  Pandangan   projections  (b)        Plan / Pelan
             = 90   = 30° × 2  dari  Unjuran ortogon
 = 60°                                                         Plan / Pelan
 3     ∠KML = 90°                                                                              2 cm
    (ii)  tan ∠NDB =   Plan/Pelan                                          2 cm
 9     y = 180° – 90° – 30°                                                           4 cm
  
 ∠NDB = tan –1 3     y = 60°                               Y     4 cm     X
 9
 = 18.43°  (b)  (i)   x = 180° – 38°   X
           = 142°
 ∠ADB = 2 × ∠NDB                                          X                     Y
           = 36.9°
    (ii)  ∠MGP = x (minor arc)
          = 142°
 (b)  (i)   x = 90° – 50°          ∠MGP = 360° – 142° (major arc)  Y    2 cm                   2 cm
          = 40°          = 218°
         y = 218° ÷ 2                                                                 4 cm
    (ii)  ∠LOA  = 65° × 2  = 109°    2.  (a)  ✓  ✗  ✓   (b)  ✗  ✓  ✓  2 cm
 = 130°    3.  (a)           (b)
 180° – 130°     (iii)  x + y = 142° + 109°
         ∠OAL =            = 251°
 2
             = 25°                                        (c)
 (c)  x  = 180° – 90° – 70°    4.                                               Plan / Pelan
        ∠BAL = ∠BLK
           y + 25° = 50°  = 20°  (a)   Plan / Pelan  Plan / Pelan   Plan / Pelan  1.25 cm   1.25 cm
 y = 25°
                                    2 cm                          1.5 cm  1.5 cm

    (iii)  x + y  = 40° + 25°   HOTS Challenge
 = 65°      4 cm                            2 cm                            X                  4 cm
 S = 2πr = 60 cm                                          2 cm          4 cm
 (c) ∠CAB = 40°  22  A
 2 ×    × OE = 60 cm      X                                    2.5 cm
 7                                                          Y
    ∠  ABC = (180° – 40°) ÷ 2   OE = 60 × 7 ÷ 44 = 9.55cm  Y  2 cm
 = 70°  l  30 cm                                                                      2.5 cm
 AE = 30  + 9.55  = 31.48cm  X  Y
 2
 2
    ∠  CBE  = 180° – 70°                                  X                     Y
 = 110°  B / E   r  O
    x = 180° – 110° – 40°                                                0.8 cm   1.5 cm   1.5 cm
 = 30°                  4 cm                 4 cm
                                                                         2 cm
                                                                                               2 cm
                                                                4 cm
                                                                                      2.5 cm
               2 cm                 2 cm


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 A15



 BOOKLET ANS MATH F3.indd   15                                                            03/01/2020   10:20 AM
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