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 Mathematics  Form 3  Chapter 5 Trigonometric Ratio

 (c)  (i)  cos 40° =   AC    CHAPTER
 22  HOTS Challenge  6   Angles and Tangents of Circles
 AC = 22 cos 40°
 AC = 16.85 m  Let the length of ladder be x  Sudut dan Tangent bagi Bulatan
 1.6
   cos 65° =
    (ii)  sin 40° =   BC  x
 22  1.6
 BC = 22 sin 40°   0.4226 =   x    1.                    2.
 BC = 14.14 m     x = 3.79 m  Diagrams     Values
                                            nilai
                 Rajah                                                               Relationship
                                               °
 DC                                          x( )
           tan 52° =                                                                   between x
 14.14    (a)                                             Circles /Bulatan               and y
 DC = 14.14 tan 52°  x                                                                  Hubungan
 DC  = 18.10 m                                                                        antara x dan y
                    O
                                             40
                   80°
                                                            x
                                                                     y
                                                                                       x + y = 90°
                                                                O
          (b)

                                             28
                   O
                      x°                                    x        y                    x = y
                                                                O

          (c)
                  x
                                                                  y
                       28°
                                             42                  O
                                                                x                         x = y


                     2 cm
          (d)
                                                               x  y
                     x
                   O
                   126°                      90
                                                                                         x = 2y
                   6 cm


       3.  (a)  x = 60° ÷ 2 = 30°                        4.  (a)  ∠DCB = 150° ÷ 2 = 75°
         (b)  Major ∠AOC                                       x = 180° – 75° = 105°
               = 360° – 100°
              =  260°
              x = 260° ÷ 2 = 130°                                Major ∠DOB = 360° – 150°
                                                                              = 210°
         (c)  Minor ∠POQ = 360° – 280° = 80°                     x = 210° ÷ 2 = 105°
              ∠  PRQ = 80° ÷ 2 = 40°
              x = 180° – 40° =140°







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 A13



 BOOKLET ANS MATH F3.indd   13                                                            03/01/2020   10:20 AM
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