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Additional Mathematics  SPM  Chapter 2 Differentiation

                                       y                                             y = f(x)
                                             f(x) = x 3
                                                                               (function of the curve)
                                    t 2
                               tangent  O  t 1  x                                   dy  = f'(x)
                                                                                    dx
                   3.  The gradient of the tangents at the moment  t    (first derivative of the function of the curve)
                                                           1
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                     and t  is the changes of f(x) as the result of the
                         2
                     changes in time which is the speed that is shown     7.  The use of the idea of limit in deriving the first
                     through the motion of the object at the instance   derivative of a function  f(x) is known as the
                     t  or t .                                      differentiation through first principle.
                      1  2
                  4.  The gradient of the tangent which happens at the
                     instance t  and t  can be determined through the      2
                                  2
                             1
                     idea of limit, that is:                    Determine the first derivative of each of the following
                                  y                             function f(x) through first principle.
                                                                (a)  f(x) = 2x       (b)  f(x) = 5x
                                                                                                2
                                       Q (x y )
                             chord        2,  2                 (c)  f(x) = 3x  – 8x    (b)  f(x) =  6
                                                                          2
                                                                                              x
                                    P     tangent               Solution
                                      (x y )
                                       1,  1
                                 O   x 1          x             (a)  Let y = f(x),        Assuming that x
                                     (t )
                                     1                             that is y = 2x         experiences a small
                     Observe that when the point Q is approaching       y + dy  = 2(x + dx)   change (dx) which
                     point P, the chord PQ is gradually approaching                       causes a small
                     and overlapping with the tangent at point P.      2x + dy  = 2x + 2dx   change (dy) in y.
                                                                           dy  = 2dx
                     Through the idea of limit, the gradient of tangent    dy   = 2     Simplify until  dy   is
                                                                                                  dx
                     of the curve at point P, m =   lim    y  – y 1  .     dx           obtained by substituting
                                                  2
                                            x  → x
                                            2  1 x  – x 1              lim dy           y = 2x.
                                                  2
                     Assuming dx = x  – x  and dy = y  – y ,       \   dx → 0  dx   = 2
                                      1
                                                   1
                                               2
                                   2
                     when x  → x , dx → 0.                             and  dy   = 2  Use the idea of limit so
                                                                                      that the first derivative of
                           2
                               1
                                y  – y
                            lim
                     \ m =  x  → x 1 x  – x 1 1                            dx         function f(x) is obtained.

                                 2
                            2
                                 2
                         =  lim    dy                           (b)  Let y = f(x),  2
                                                                   that is y = 5x

                            dx → 0  dx
                                                                        y + dy  = 5(x + dx)
                                                                                       2
                                  SPM Tips                            5x  + dy  = 5[x  + 2xdx + (dx) ]
                                                                        2
                                                                                              2
                                                                                  2
                                                                      5x  + dy  = 5x  + 10xdx + 5(dx)
                                                                        2
                                                                                               2
                                                                                 2
                  dx and dy is read as “delta x” and “delta y”.
                                                                           dy  = 10xdx + 5(dx)                  Form 5
                                                                                           2
                                                                           dy   = 10x + 5dx
                               dy                                          dx
                  5.  The symbol    is used to represent the gradient
                               dx                                      lim dy
                     m which is obtained through the idea of limit      \   dx → 0  dx   = 10x + 0
                     and is known as gradient function, that is            dy
                                                                       and     = 10x
                                                                           dx
                                   dy  =   lim dy
                                   dx  dx → 0  dx                   REMEMBER!
                                                                                              2
                  6.  The gradient of function  dy  is the first derivative   Be careful with the expansion of (x + dx) . Observe that
                                                                 dx  ≠ (dx) .
                                                                   2
                                                                        2
                                         dx
                     of function f(x), that is
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