Page 39 - Hybrid PBD 2021 Form 2 - Matematik
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BAB


                     2             Pemfaktoran dan Pecahan Algebra



                                   Factorisation and Algebraic Fractions





               PBD
               PBD    2.1  Kembangan                                                          Video            Buku Teks
               PBD
                             Expansion                                                                         ms. 21 – 27
                   FOKUS TOPIK

                •  Kembangan  ungkapan  algebra  ialah  hasil  pendaraban  satu  atau  dua
                  ungkapan dalam kurungan.                                                     Tip Penting
                   Expansion of algebraic expression is a product of one or two expressions in brackets.
                •  Kembangan ungkapan algebra boleh dilakukan dengan mendarabkan          a(x + y) = ax + ay
                  sebutan di luar kurungan dengan setiap sebutan di dalam kurungan.       (a + b)(x + y)
                   The expansion of algebraic expressions can be performed by multiplying the term outside of
                  the brackets with each term inside the brackets.
                                                                                          = a(x + y) + b(x + y)
                                                                                          = ax + ay + bx + by



                1.  Cari kembangan bagi setiap yang berikut berdasarkan jubin algebra yang diberi.    SP 2.1.1     TP2
                  Find the expansion of each of the following based on the given algebraic tiles.

                                                    (a)  3x(2 + x)                   (b)  (x + 5)(2x + 1)
                    5(x + 3)
                                                                2       x                    x       5
                          x        3
                                                                                         2x  2x 2    10x
                                                         3x     6x     3x 2
                    5     5x      15                                                      1  x        5
                                         Luas jubin
                                         Area of tile
                    5(x + 3)                            3x(2 + x)                       (x + 5)(2x + 1)
                                                                                            2
                    = 5x + 15                           = 6x + 3x 2                     = 2x  + 10x + x + 5
                                                                                        = 2x  + 11x + 5
                                                                                            2

                                                    (c)  (2x + 3)(x – 2)             (d)  (3x – 4)(2x – 3)
                    (x – 1)(x + 2)                              2x          3                       3x
                              x         2                                                            8x –12   2x – 3
                                                     x – 2     2x  – 4x    3x – 6
                                                                2
                                                                                x
                                                                                         2x
                     x – 1  x  – x    2x – 2           2                                     9x – 12   12     3
                             2
                                              x
                       1                                                                     3x – 4    4
                                                        (2x + 3)(x – 2)
                                                           2
                    (x – 1)(x + 2)                      = 2x  – 4x + 3x – 6             (3x – 4)(2x – 3)
                                                           2
                    = x  – x + 2x – 2                   = 2x  – x – 6                   = 6x  – (9x – 12) – (8x – 12) – 12
                      2
                                                                                            2
                    = x  + x – 2                                                        = 6x  – 9x + 12 – 8x + 12 – 12
                      2
                                                                                            2
                                                                                        = 6x  – 17x + 12
                                                                                            2
                           Tip Penting
                       –(a + b) = –a – b
                       –(a – b) = –a + b
                       –(–a + b) = a – b
                       –(–a – b) = a + b
                                                                12
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         Bab 2.indd   12                                                                                            9/3/21   5:13 PM
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