Page 46 - Hybrid PBD 2021 Form 2 - Matematik
P. 46

Matematik   Tingkatan 2  Bab 2
                  11.  Faktorkan setiap ungkapan berikut.   SP 2.2.2     TP3
                     Factorise each of the following expression.                                               E-pop Quiz


                      Pendaraban silang / Cross multiplication         Faktor sepunya dalam empat sebutan algebra
                                                                       Common factor in four algebraic terms
                              y  – 8y + 15  Pendaraban faktor 15:
                               2
                                                                            2
                                            Factor multiplication of 15:  xy – y  – 4x + 4y   Gabungkan sebutan dengan faktor
                                            (–1) × (–15) → (–1) + (–15) = –16  2              sepunya dalam satu kurungan.
                                            (–3) × (–5) → (–3) + (–5) = –8  = (xy – y ) + (–4x + 4y)   Combine the terms with common factor
                                                                       = y(x – y) – 4(x – y)  in one brackets.
                      Pendaraban          y       –3 –3y               = (x – y)(y – 4)
                      silang:          (×)  y     –5 –5y  (+)
                      Cross                                             Faktor sepunya.  Faktorkan.
                      multiplication:     y 2    +15 –8y                 Common factor.  Factorise.

                      y  – 8y + 15 = (y – 3)(y – 5)
                       2
                      (a)  p  – 4p – 12                                (f)  ab + ac + bd + cd
                          2
                         = (p + 2)(p – 6)                                 = (ab + ac) + (bd + cd)
                                                                          = a(b + c) + d(b + c)
                                                p       +2 +2p
                                            (×)                  (+)      = (b + c)(a + d)
                                                p       –6 –6p
                                                p 2    –12 –4p



                      (b)  6m  – m – 2                                 (g)  pq – p  + 3q – 3p
                                                                                2
                            2
                         = (3m – 2)(2m + 1)                               = (pq – p ) + (3q – 3p)
                                                                                  2
                                               3m      –2 –4m             = p(q – p) + 3(q – p)
                                           (×)                  (+)
                                               2m      +1 +3m             = (q – p)(p + 3)
                                               6m 2    –2 –m



                      (c)  –6x  – 7x + 5                               (h)  bm – bn + cm – cn
                            2
                         = (–3x – 5)(2x – 1)                              = (bm – bn) + (cm – cn)
                                               –3x     –5 –10x
                                           (×)                  (+)       = b(m – n) + c(m – n)
                                                 2x    –1 +3x             = (m – n)(b + c)
                                               –6x 2   +5 –7x




                      (d)  k  – 12k + 36                               (i)  wp – hp – wq + hq
                          2
                         = (k – 6) 2             k      –6   –6k          = (wp – hp) – (wq – hq)
                                             (×)                  (+)
                                                 k      –6   –6k          = p(w – h) – q(w – h)
                                                 k 2   +36 –12k           = (w – h)(p – q)






                           2
                                                                             2
                      (e)  8t  + 29t – 12                              (j)  3h  + 12h – 2hk – 8k
                         = (8t – 3)(t + 4)       8t     –3    –3t         = (3h  + 12h) – (2hk + 8k)
                                                                               2
                                             (×)                  (+)
                                                    t   +4 +32t           = 3h(h + 4) – 2k(h + 4)
                                                 8t 2  –12    29t         = (h + 4)(3h – 2k)







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         Bab 2.indd   19                                                                                            9/3/21   5:13 PM
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