Page 49 - Hybrid PBD 2021 Form 2 - Matematik

Matematik Tingkatan 2 Bab 2
14. Permudahkan setiap yang berikut. SP 2.3.2 TP3
Simplify each of the following.

Pendaraban ungkapan algebra Pembahagian ungkapan algebra
Multiplication of algebraic expressions Division of algebraic expressions
2m – 2n × 4x + 4y Faktorkan sebutan sepunya. 4b ÷ a + 1
x + y 10 Factorise common term. 2b + 1 5b Tukar ÷ kepada × dan salingan
5b
1 1 4b 5b a + 1 ialah a + 1 .
5b
= 2(m – n) × 4(x + y) Pemudahkan = 2b + 1 × a + 1 Convert ÷ to × and the reciprocal of
x + y 1 10 5 Simplify 2 a + 1 is a + 1 .
5b
5b
20b
= 4(m – n) = (2b + 1)(a + 1)
5
3m m + m – 6 4a – 4b a – b
2
(a) × (e) ÷
m – 9 6m 2 9b 18a
2
1 1 1 2
= 3m × (m – 2)(m + 3) = 4(a – b) × 18a
(m – 3)(m + 3) 6m 2 9b a – b
1 2m 1 1
(m – 2) 8a
= =
2m(m – 3) b

p + p q + 2 3q – 1 q – 5
2
(b) × (f) ÷
2pq + 4p 3p + 3 3q – 21 4q – 28
1 p(p + 1) 1 q + 2 1 1
= × 3q – 1 4(q – 7)
2p(q + 2) 3(p + 1) = 3(q – 7) × q – 5
1 1 1 1
1
= = 4(3q – 1)
6 3(q – 5)

2
1 3x + 3y x – y 2
(c) × xy + x y (g) ÷
2
1 – x 2 4z + 2 4z + 4z + 1
2
1 1 1 1
= × xy(1 + x) 3(x + y) (2z + 1)(2z + 1)
(1 – x)(1 + x) 1 = 2(2z + 1) × (x + y)(x – y)
1
= xy 3(2z + 1) 1
1 – x =
2(x – y)

2
my – ny x – y 2 (y + 3) 2 3y + 9
(d) × (h) ÷
x + y m – mn 16 – x 2 8 – 2x
2
1
y(m – n) 1 (x + y)(x – y) (y + 3) 2 8 – 2x
= × = 4 – x 2 × 3y + 9
2
x + y 1 m(m – n) 1
y(x – y) (y + 3)(y + 3) 1 2(4 – x) 1
= = ×
m (4 + x)(4 – x) 1 3(y + 3) 1
2(y + 3)
=
3(4 + x)

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Bab 2.indd 22 9/3/21 5:13 PM