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(c)  8! × 2! × 2 = 161280                           T  – T  = (x + 1)y – xy
                                                                           2
                                                                               1
                                                            [3]           d = xy + y – xy
                    12.  (a)  P  = 720                                    d  = y
                         6
                           6                                               2
                                                            [1]           d  = d  = y
                                                                           2
                                                                               1
                      (b)  3! × 3! = 36                                                                      [2]
                                                            [2]        (b)         24 = xy + 8y
                          2! × 4! × 3  1
                      (c)           =                                              24 = (2y)y + 8y
                             6 P     5                                       2
                               6                            [3]            2y  + 8y − 24 = 0
                                                                                    y = 6 (rejected) or y = 2
                       5
                           5
                    13.  ( C  ×  C  ×  C ) × 3 = 1500
                                5
                        3    3   4                                        When y = 2, x = 4
                                                            [4]           Area of first rectangle = xy = 2x = 8 cm 2
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                                   47
                    14.  ( C  ×  C ) + ( C  ×  C ) +  C  = 2.309 × 10 16                                     [2]
                       47
                                        53
                                              47
                            53
                         23    2     24    1    25
                                                            [4]                 a    120
                                                                     2.  (a)  S  =    =
                          5
                       3
                    15.  ( C )  = 243                                      ∞   1 – r  9
                        2                                                      120(1 – r)
                                                            [2]            a =           …… (1)
                                                                                   9
                      9
                    16.  C  = 126                                         Second term = ar = a –  5
                        5
                                                            [1]                              6
                                                                                             5
                         6
                    17.  (a)  C  = 15                                                  a =        …… (2)
                           2                                                               6(1 – r)
                                                            [2]
                         6
                      (b)  C  = 6                                         Equation (1) = Equation (2)
                           5                                               120(1 – r)    5
                                                            [2]                      =
                                                                               9       6(1 – r)
                           5
                      12
                    18.  C  ×  P  = 95 040
                                                                             3
                                                                                              5
                        5    5                                            r =   (accepted) and r =   (rejected because it
                                                            [2]              4                4
                                                                          leads to a negative first term)
                    19.  C  ×  C  ×  P  = 64800
                               6
                      6
                          4
                        4   2    6
                                                            [2]           a =  10  (accepted) and a =  –10  (rejected
                                                                                                3
                                                                              3
                    20.  (a)  C  ×  C  = 840                              because all the terms are positive)
                         8
                              6
                           3    4
                                                            [2]                                              [4]
                                   6
                               8
                                         8
                                             6
                      (b)  840 + ( C  ×  C ) + ( C  ×  C ) = 1016      (b)  S  – S
                                 2   5     1   6                           7   5
                                                            [3]                10     3  7
                                                                                  1 –
                      (c)  C  – 1016 + 840 = 3256                              3  1 1 2 2   70985
                         14
                                                                                      4
                            7                                             S  =             =
                                                            [3]            7         3       6144
                                                                                 1 –
                              6
                                        6
                         12
                    21.  (a)  C  –  C  – ( C  ×  C ) = 696                           4
                                   6
                            5   5    4    1                                             5
                                                                                      3
                                                            [4]                10 1 1 2 2
                                                                                  1 –
                      (b)  More pianists than violinists                  S  =   3    4    =  3905
                                                2
                            2
                         = ( C  ×  C ) + ( C  ×  C ) + ( C  ×  C  ×  C )   5     1 –  3     384
                                                         4
                                                    6
                                      2
                                4
                                          4
                                                      1
                                        1
                                  3
                                                          2
                             2
                                            4
                                                  2
                         = 42                                                        4
                         Same number of pianists and violinists            70985  –  3905  =  2835  = 1.38
                            6
                                4
                         = ( C  ×  C  ×  C ) + ( C  ×  C  ×  C )           6144   384   2048
                                          6
                                                   2
                                              4
                                    2
                                      2
                                  1
                             2
                                                3
                                                     1
                                            1
                         = 108                                                                               [3]
                         12 C  – 42 – 108 = 642                      3.  Fourth term
                            5
                                                            [7]        = ar n – 1
                                                                         a
                                                                          2
                                                                       =  1 2 (r)
                                                                              3
                    11   Series                                           2 2
                                                                       =  8a
                                                                         54
                    1.  (a)  T  = xy                                   r  =  8a 2   ×  2
                                                                        3
                           1
                         T  = (x + 1)y                                     54  a 2
                           2
                         T  = (x + 2)y                                 r  =  2
                           3                                               3
                         T  – T  = (x + 2)y – (x + 1)y                              a 2
                              2
                           3
                         d = xy + 2y – xy – y                          S  =   a   =   1 2   =  3a 2
                                                                                    2
                         d  = y                                         ∞  1 – r     2     2
                          1                                                       1 –
                                                                                     3                       [5]
                         Cambridge IGCSE
                                          TM
                  194     Ace Your Additional Mathematics
         Answers Add Math.indd   194                                                                             14/03/2022   12:29 PM
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