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→    →    →
                    12   Vectors                                     6.  AB  = AO + OB
                                                                             7
                                                                                  –10
                                                                                 +
                                                                          = 1 2 1 2
                          →                                                  –4   –12
                                    2
                                         2
                    1.  (a)  |AB| = √(–4)  + (3)                              –3
                                                                             –16
                              = √25                                       =   1 2
                              = 5                                      →       –3
                                                            [1]        AC = 3  1 2
                                                                              –16
                      (b)   1 (–4i + 3j)
                                                                              –9
                          5                                 [1]           =   1 2
                                                                             –48
                                                                       →
                                                                            →
                                                                                 →
                    2.  |p – q + r|                                    OC = OA + AC
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                                            4
                                                 3
                                  2
                                                   u
                                         1
                                              2
                        u
                      =  3i – (–2i) –  i + 5j –  –  i  +  14 j            =   1 2 1 2
                                                                             –7
                                                                                    –9
                                                                                 +
                                  3
                                            7
                                                                              4
                                u
                      =  u 13 i +  81 j                                   =   1 2     –48
                                                                             –16
                             14
                         3
                                                                             –44
                          13
                                81
                             2
                      =   1 2 1 2  2                                   |OC| = √(–16)  + (–44)
                              +
                                                                        →
                                14
                          3
                                                                                  2
                                                                                         2
                      = 7.23                                               = 4√137
                                                            [3]                                              [4]
                                                                       →
                                                                            2 →
                              1
                      u
                                u
                    3.  2c – a +  b                                  7.  BC =  (AC)
                                                                            5
                              5
                                                                       →
                                                                                 2 →
                                                                            →
                                                                                        →
                                4
                                               1
                            7
                                  2 1
                        u 1
                                                    u
                      =  2 –  i +  j  –   –3i + 5j 2  +  (–6j)         BO + OC =  (AO + OC)
                                                                                 5
                                               5
                            3
                                        2
                                5
                                                                                           2
                                        5
                                            6
                               3
                                   8
                                              u
                        u
                      =  –  14 i +  i +  j –  j –  j                   –µ(–2i + j) + l(–3i – 8j) =  [−(4i − 5j) + l(−3i − 8j)]
                                                                                           5
                                   5
                               2
                          3
                                            5
                                        2
                                                                                             8
                                                                                                 6
                                                                                   2µ – 3l = –   –  l
                                                                                             5
                                                                                                 5
                                  u
                        u
                      =  –  19 i +  21 j                                         10µ – 15l = –8 – 6l
                          6
                               10
                              2
                                  21
                         1
                      =  –  19 2 1 2 2                                                10µ = 9l – 8
                                +
                                                                                           9l – 8
                                  10
                            6
                                                                                        µ =
                      = 3.8                                                                  10 16
                                                            [3]                    –µ – 8l = –2 –   l
                                                                                                5
                    4.  a(–3i + 5j) + 10j  = b(6i)                                      µ = –8l +  16 l + 2
                                –3a = 6b                                                         5
                                  a = –2b                                               µ = –  24 l + 2
                                                                                             5
                             5a + 10 = 0                                            9l – 8  –24l + 10
                          5(–2b) + 10 = 0                                            10   =    5
                                  b = 1                                             9l – 8 = –48l + 20
                                  a = –2
                                                            [3]                       57l = 28
                          →    →    →                                                   l =  28
                    5.  (a)  AB  = AO + OB                                                 57
                             = 3i – 7j + 6i – j                                              24 28
                                                                                               1 2
                             = 9i – 8j                                                  µ = –   5 57   + 2
                                                            [2]                              34
                          1 →    →                                                        = –
                      (b)   AB  = CB                                                         95
                          3                                                                                  [7]
                          1 →    →   →
                           AB  = CO + OB                                      −3 × 5 + 13 × 3
                          3                                          8.  (a)  d =
                           →     →   1 →                                           8
                            OC  = OB –  AB                                  = 3
                                     3                                     e × 5 – 20 × 3
                                      1
                               = 6i – j –  (9i – 8j)                            8       = 0
                                      3                                              5e  = 60
                                    5
                               = 3i +  j                                             e  = 12
                                    3
                                                            [2]                                              [4]
                         Cambridge IGCSE
                                          TM
                  198     Ace Your Additional Mathematics
         Answers Add Math.indd   198                                                                             14/03/2022   12:29 PM
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