Page 44 - Hybrid PBD 2022 Tg 5 - Matematik Tambahan
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Matematik Tambahan  Tingkatan 5  Bab 2 Pembezaan
                  8.  Cari terbitan pertama terhadap x bagi setiap fungsi yang berikut.
                     Find the first derivative with respect to x for each of the following.    SP 2.2.2    TP3


                                                                       (i)    dy   =   d  (–x ) –   d  (3x ) +   d  (2)
                                                                                     3
                                                                                             2
                      (i)  y = –x  – 3x  + 2                              dx    dx      dx       dx
                                   2
                              3
                                                                                   2
                             (x – 2)(3 – 2x)                                  = –3x  – 6x
                      (ii)  y =
                                  x                                                   2
                                                                       (ii)  y  =  3x – 2x  – 6 + 4x
                                                                                       x
                             Tip Penting                                                 6
                                                                              = –2x + 7 –
                         Guna/Use                                                        x
                         y = f(x) = h(x) ± g(x),                              = –2x + 7 – 6x –1
                              dy  df(x)  d                                dy                   6
                         maka    =    =    h(x) ± g(x)                                –2
                              dx  dx   dx                                 dx   = –2 + 6x  = –2 +  x 2
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                                                                                        2
                      (a)  f(x) = 2x 3  1  –  3                      (b)   y =  x ( x – x )
                                      x
                                  4
                                                                             y = x – x 5 2
                                  1
                           f(x)  =  x  – 6x 2                              dy      5  3
                                    3
                                  2                                           = 1 –  x 2
                                  3                                        dx      2
                           f’(x)  =  x  – 12x                                      5
                                    2
                                  2                                           = 1 –    3
                                                                                      x
                                                                                   2

                  9.  Cari nilai terbitan pertama terhadap x untuk setiap fungsi berikut bagi nilai x yang diberikan.
                     Find the value of the first derivative with respect to x for each of the following functions with the given value of x.    SP 2.2.2    TP3


                                                                                          3
                        y  =   2 – x  2 , x = –2                      (a)  y =  (2x + 3)(1 – x ) , x = –1
                                                                                   3x
                                                                                     2
                               4
                                                                                        4
                             1                                                y  =  2x – 2x  + 3 – 3x 3
                         y  =   [4 – 4x + x ]                                           3x 2
                                        2
                            16                    Tip Penting
                                                                                  2
                                                                                         2
                            1   1     1                                       y  =  x   –  x  + x  – x
                                                                                     –1
                                                                                           2
                                                                                               –2
                           =   –  x +   x 2   Ungkapkan dalam sebutan             3      3
                            4   4    16       berasingan dahulu.
                                                                                             1
                                                                                       4
                       dy     1   1           Express in separate terms first.   dy   =  –2  –  x –    – 1
                           = –  +  x                                         dx   3x 2  3    x 3
                       dx     4   8                                                      dy    –2   4
                                          dy     1   1                     Apabila x = –1,     =    +   + 1 – 1
                      Apabila/When  x  = –2,     = –   +  (–2)                           dx    3    3
                                          dx     4   8                     When            2
                                                 1                                       =
                                              = –                                          3
                                                 2
                                                                                    1
                                                                                            1
                                  
                               4x   2 –  1    1                       (c)  y = x 3 –   , x =
                                 3
                                                                               3
                                                                                       2
                      (b)   f(x) =     x  , x = –                                   2x      3
                                   7x 2        2                                        3    1
                                                                                   3
                                 4       1                                    y  = x 9 –   +  
                                    
                           f(x)  =  x  2 –                                             x   4x 2
                                 7       x                                                  1
                                 8    4                                       y  = 9x  – 3x  +  x
                                                                                    3
                                                                                         2
                                =  x –                                                      4

                                 7    7                                      dy              1
                                 8                                               = 27x  – 6x +
                                                                                     2
                           f‘(x)  =                                          dx              4
                                 7                                                    1 dy       1      1    1
                                                                           Apabila x =  ,     = 27    – 6     +  4
                                                                                      3 dx
                                                                                                        3
                                                                                                 9
                                                                           When
                                                                                            = 1 1
                                                                                               4
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         02 Hybrid PBD Mate Tamb Tg5.indd   23                                                                    09/11/2021   9:24 AM
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