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Matematik Tingkatan 2 Jawapan
4. 5. (a) 1
Kesudahan putaran ialah (4, 5). 3 1 3
The outcome of rotation is (4, 5). (b) (i) 4 (ii) 4
Mungkin
Kesudahan putaran ialah (5, 6). Possible (c) 805
(d) Kotak G / Box G
The outcome of rotation is (5, 6).
6. (a) {E, A, I }
Terdapat 9 kesudahan yang 52
mungkin bagi putaran itu. Tidak mungkin (b) (i) 55
There are 9 possibility outcomes Impossible (ii) RM1 248
for the rotation.
(c) (i) 0.35
Ruang sampel bagi hasil tambah (ii) 0.3
dua nombor yang diperolehi ialah Pasti (iii) Apabila bilangan percubaan cukup besar,
{8, 9, 10, 11, 12, 13, 14}. Sure kebarangkalian eksperimen mendapat butang
The sample space of the sum of hitam akan menghampiri kebarangkalian teori.
both numbers obtained is When the number of trials is large enough,
{8, 9, 10, 11, 12, 13, 14}. the experimental probability of getting a black
button will be converging to the theoretical
probability.
C
1. (a) Pilihan Pilihan kedua KBAT
pertama Second Keudahan (i) 50
First picked picked Outcomes (ii) 12
C CC
MARKAH
Penilaian Pra-PT3
Penilaian Pra-PT3
Penilaian Pra-PT3
C A CA
T CT A
1. B 2. C 3. C 4. D 5. A
C AC
6. D 7. C 8. C 9. B 10. A
A A AA 11. D 12. D 13. A 14. B 15. D
16. C 17. C 18. D 19. B 20. D
T AT
B
C TC 21. (i) Diameter (ii) Perentas / Chord
(iii) Sektor / Sector (iv) Tembereng / Segment
T A TA
22.
T TT
(b) (i) {(C, A), (A, C)} (ii) {(C, C), (A, A), (T, T)}
1
(c) (i) (ii) 12 biji / marbles
5
2. (a) (i) M = {1, 2} (ii) N = {1, 2, 3, 6}
(iii) P = {2, 3, 5}
2 2
(b) (i) (ii)
3 5
(c) 1 batang / pen (x + y) 2 (x + y) 3
51 23. 2xy 2 ÷ 2x – 4xy
2
3. (a)
100 (x + y) 2 2x – 4xy
2
2
(b) (i) R = {2, 3, 5, 7, 11, 13, 17, 19}, P(R) = = 2xy 2 × (x + y) 3
5
(ii) G = {1, 3, 5, 7, 9, 11, 13, 15, 17, 19}, P(G) = 1 2 (x + y) 2 2x(x – 2y)
(c) 10 = 2xy 2 × (x + y) 3
5 3 7
4. (a) (b) (i) (ii) x – 2y
26 10 10 =
2
(c) 1 y (x +y)
6
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