Page 18 - PRAKTIS HEBAT MATHS TG 2

Matematik Tingkatan 2 Jawapan

The appropriate measure of central tendency is 5. (a) 6
mean because mean takes the marks for all criteria (b) 3
and can be used to determine the winner. Mode (c) (i) p = 12, q = 68, r = 72, s = 79
and median cannot give any significant meaning (ii) Agus yang layak mewakili sekolah kerana julat
about the winner of the competition. markahnya adalah kecil berbanding Sawing.
Ini bermakna, Agus adalah lebih konsisten
2. (a) (i) Bilangan buku Kekerapan Titik tengah berbanding Sawing. Median dan min bagi Roy
Number of books Frequency Midpoint adalah yang paling rendah berbanding Agus
5 – 9 9 7 dan Sawing.
10 – 14 11 12 Agus is qualified to represent the school
15 – 19 x 17 because the range of his mark is smaller
than Sawing. This means that, Agus is more
20 – 24 2 22 consistent than Sawing. Median and mean
for Roy is the lowest compared to Agus and
(ii) 8 Sawing.
(b) (i) Bagi gerai A, sukatan kecenderungan memusat
yang sesuai ialah median kerana terdapat nilai KBAT
ekstrem, iaitu 45 dalam data tersebut.
Median = 80 Pasukan B / Team B
Bagi gerai B, sukatan kecenderungan memusat
yang sesuai ialah min kerana taburan markah
adalah sekata. Min = 79
13
For stall A, the appropriate central of tendency Prakt is PT 3 Kebarangkalian Mudah
is median because there is an extreme value, Simple Probability
which is 45 in the data. Median = 80
For stall B, the appropriate central of tendency
is min because the distribution of the marks is A
uniform. Mean = 79
(ii) Julat gerai A / Range of stall A = 42 1. D 2. B 3. B 4. A 5. C
Julat gerai B / Range of stall B = 12 6. C 7. B 8. C 9. A 10. D
Gerai B kerana secara keseluruhan, markah B
bagi gerai B adalah lebih tinggi (min B >
min A) dan lebih konsisten (julat B < julat A)
berbanding gerai A. 1. (a) 6, 7, 8, 9 3
Stall B because as overall, the mark for stall (ii) (iii) ✗
B is higher (mean B > mean A) and more (b) (i) 3 3
consistent (range B < range A) than stall A. 2.
(c) (i) Median = 75 RM200
(ii) Median tidak berubah.
Median would not change. Pulau Langkawi RM300
3. (a) Min. Min = 7.6% Langkawi Island
Mean. Mean = 7.6% RM500
(b) Mod / Mode = 5
Median = 3
Min / Mean = 3.5 RM200
(c) (i)
Perbelanjaan (RM) Gundalan Bilangan keluarga Pulau Tioman RM300
Tioman Island
Expenses (RM) Tally Number of families
100 – 149 |||| 4 RM500
150 – 199 |||| || 7 S = {(Pulau Langkawi / Langkawi Island, RM200),
200 – 249 |||| |||| |||| ||| 18 (Pulau Langkawi / Langkawi Island, RM300),
250 – 299 |||| |||| |||| |||| 19 (Pulau Langkawi / Langkawi Island, RM500),
(Pulau Tioman / Tioman Island, RM200),
300 – 349 |||| |||| || 12 (Pulau Tioman / Tioman Island, RM300),
(ii) RM247.83 (Pulau Tioman / Tioman Island, RM500)}
4. (a) 0 3. (a) (i) Tidak mungkin / Not possible
(b) (i) Mod = Rabu (ii) Mungkin / Possible
Mode = Wednesday (b) S = {27, 29 , 31 , 37, 41, 43 , 47, 49}
(ii) Min / Mean = RM54
(c) (i) Melayu / Malay P(A) = 8
(ii) 180 orang / people 23

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