Page 34 - Hybrid PBD 2021 Form 1 - Matematik
P. 34

Matematik  Tingkatan 1  Bab 1
                  18.  Hitung setiap yang berikut.   SP 1.3.3      TP3
                     Calculate each of the following.

                                                          1
                                                                2
                                                                                            3
                                                                                                
                                                      (a)   3  24  ÷  4              (b)  –3  +  –7 1 2  ×  3
                                                             –  –
                                                                5
                                                                                                        4
                                                                                                   3
                                                                                            5
                                1
                            
                         2 ×  –1  +  3 2                  4  1  2    4 5                  = –3  +  –  22   ×  3 2
                                                                                              3
                                                                                                  
                                4
                                   8
                                                                                              5
                                                                                                     3
                                 5
                              
                         = 2 ×  –   +  3 2               =   4 5  +  5 2  ÷  5  4        = –3  +  –  11 2  4
                                                                                              3
                                     8
                                 4
                                                                                                  
                                                                 8
                                                                                              5
                                                            20
                              
                         = 2 ×  –  10  +  3 2            =  13   +  5 20 1 2  ÷  5       = –  18  –  11   2
                                      8
                                 8
                                                                                                  2
                                                                                              5
                               2
                          1
                         = 2 ×  –  7                     =  20 4   ×  4                   = –  36  –  55
                                 8
                         = –1 3   4                      =  13                               10   10
                                                            16
                             4                                                            = –  91
                                                                                             10
                                                               Tip Penting                     1
                                                                                          = –9
                                                                a  ÷   =    ×  d              10
                                                                      a
                                                                   c
                                                                b  d  b   c
                            1    3   2                     3    1   2                      5     1      8    1
                                                                                                2  2
                      (c)  –8  ÷ 2    +               (d)  1  – 2    +   ÷ 3          (e)  2  –  –    ÷  –   +
                            6    4   11                    5    3   5                      8     5      5    4
                             49   11   2                     3   1   2                       5     1      8   1
                                                                                                 2  2
                         = –    ÷    +                   = 1  – 2  +    ÷ 3               = 2  –  –    ÷  –   +
                             6    4  2  11                   5   3   5                       8     5      5   4
                                                                     2
                                                             3
                                                                 1
                                                                                             5
                                                                                                
                         = –  49  ×   4   +   2          = 1  – 2  +   ×  1               = 2  –  –  1  × –  5 2  1 +  1
                            3  6  11   11                    5   3   5   3                   8   1  5    8   4
                                                               7
                                                            8
                         = –  98  +   2                  =  –   +   2                       21  1   1
                             33   11                        5  3   15                     =  8   –   +  4
                                                                                                8
                         = –  98  +   6                  =  24  –  35  +   2                20   1
                             33   33                        15  15   15                   =  8   +  4
                         = –  92                         = –   9  3                         22
                             33                             5 15                          =  8
                         = –2 26                         = –  3                              3
                             33                              5                            = 2
                                                                                             4

                  19.  Selesaikan masalah berikut.    SP 1.3.4
                     Solve the following problems.
                     (a)  Afiqah dan Sarah berkongsi sejumlah wang untuk didermakan kepada sebuah badan kebajikan. Afiqah
                                    3                           4
                         menderma   manakala Sarah menderma        daripada wang tersebut. Siapakah yang menderma lebih
                                    5                           10
                         banyak? Berapakah lebihnya?   TP4
                                                                                                  3                   4
                         Afiqah and Sarah share an amount of money to be donated to a charity organisation. Afiqah donates   whereas Sarah donates
                                                                                                  5                  10
                         of the money. Who donates more? How much more?
                         Afiqah menderma / Afiqah donates             Beza / Difference
                         3 × 2  =   6                                 =  6   –   4              Tip Penting
                         5 × 2  10                                      10   10            Bandingkan pecahan dengan
                          6                     4                     =   2                menyamakan penyebutnya dahulu.
                             lebih besar daripada   .                   10                 Compare the fractions by equating the
                         10                    10                       1                  denominator first.
                          6    is greater than   4   .                =
                         10            10                               5
                                                1
                         Maka, Afiqah menderma   daripada wang tersebut lebih daripada Sarah.
                                          1     5
                         Hence, Afiqah donates   of  the money more than Sarah.
                                          5
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         01 Hybrid PBD Mate Tg1.indd   7                                                                          03/09/2021   3:24 PM
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