Page 31 - Hybrid PBD 2021 Form 1 - Matematik

Matematik Tingkatan 1 Bab 1
12. Permudahkan setiap yang berikut. SP 1.2.3 TP4
Simplify each of the following.

(a) –12 + (–2) × 3 – 40 ÷ (–8) (b) 56 ÷ (–2) + 3 × 7 + (–5)
–4 × [–20 + (15 – 3)] = –12 + (–6) – (–5) = –(56 ÷ 2) + 21 – 5
= –4 × (–20 + 12) = –12 – 6 + 5 = –28 + 21 – 5
= –4 × (–8) = –18 + 5 = –7 – 5
= +(4 × 8) = –13 = –12
= 32

13. Padankan hukum operasi aritmetik yang betul bagi setiap operasi berikut. SP 1.2.4 TP3
Match the correct law of arithmetic operation of each of the following operations.

4 × 5 + 4 × 8
= 4 × (5 + 8) Hukum Kalis Tukar Tertib
= 4 × 13 Commutative Law Tip Penting
= 52 Hukum operasi aritmetik:
Laws of arithmetic operations:
• Hukum Kalis Tukar Tertib
5 × 7 × 10 Commutative Law
= 7 × (5 × 10) Hukum Kalis Sekutuan a + b = b + a
= 7 × 50 Associative Law a × b = b × a
= 350 • Hukum Kalis Sekutuan
Associative Law
(a + b) + c = a + (b + c)
(a × b) × c = a × (b × c)
19 + 7 + 1 • Hukum Kalis Agihan
= 19 + 1 + 7 Hukum Identiti Distributive Law
= 20 + 7 Identity Law a × (b + c) = a × b + a × c
= 27 a × (b − c) = a × b − a × c
• Hukum Identiti
Identity Law
a + 0 = a a + (−a) = 0
1
17 × 1
17 Hukum Kalis Agihan a × 0 = 0 a × = 1
a
= 1 Distributive Law a × 1 = a

14. Selesaikan setiap yang berikut dengan pengiraan efisien tanpa menggunakan kalkulator. SP 1.2.5 TP3
Solve each of the following using efficient computations without using calculator.

(a) 25 × 43 × 4 (b) 397 × 5
499 × 4 = (25 × 4) × 43 = (400 – 3) × 5
= (500 – 1) × 4 = 100 × 43 = (400 × 5) – (3 × 5)
= (500 × 4) – (1 × 4) = 4 300 = 2 000 – 15
= 2 000 – 4 = 1 985
= 1 996

(c) 50 × 36 × 2 (d) 30 × 42 × 4 (e) 39 × 25 × 40
= (50 × 2) × 36 = (30 × 4) × (40 + 2) = (25 × 40) × 39
= 100 × 36 = 120 × (40 + 2) = 1 000 × 39
= 3 600 = (120 × 40) + (120 × 2) = 39 000
= 4 800 + 240
= 5 040

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01 Hybrid PBD Mate Tg1.indd 4 03/09/2021 3:24 PM