Page 42 - Hybrid PBD 2021 Form 1 - Matematik

Matematik Tingkatan 1 Bab 1
(ii) Ramesh bergerak 8.7 m ke arah timur, Jawapan / Answer :
kemudian 12.9 m ke arah barat. Bilangan durian yang tinggal
Seterusnya, dia bergerak sejauh 5.8 m Number of remaining durians
ke arah timur. Perihalkan pergerakan = 512 ÷ 8
Ramesh yang seterusnya supaya dia = 64 biji durian / durians
boleh berada di kedudukan asalnya. Bilangan durian pada permulaan
Ramesh moves 8.7 m to the east, then 12.9 m to Number of durians at the beginning
the west. Next, he moves 5.8 m to the east. Describe = 64 + 5 + 18
Ramesh’s next movement so that he will be at his
original position. = 87 biji durian/ durians
[3 markah / 3 marks]
Jawapan / Answer :
8.7 m – 12.9 m + 5.8 m 8. (a) Nita mempunyai RM235 di dalam bank dan
= –4.2 m + 5.8 m telah berbelanja RM321, berapakah hutang
= 1.6 m (ke barat dari titik asal) yang perlu dilangsaikan Nita?
(to the west from original position) Nita had RM235 in the bank and spent RM321, how
Mula much is the debt that she has to settle?
Start 8.7 m [2 markah / 2 marks]
12.9 m Jawapan / Answer :
5.8 m
1.6 m Berhenti Hutang Nita / Nita’s debt = 235 – 321
Stop = –86
Ramesh perlu bergerak 1.6 m ke timur Hutang Nita ialah RM86.
untuk kembali ke kedudukan asal. Nita’s debt is RM86.
Ramesh needs to move 1.6 m to the east so that he
will return to original position.
(b) Encik Wong menyimpan RM1.3 ribu setiap
bulan daripada hasil keuntungan syarikatnya
selama lima tahun. Dalam tempoh itu, dia
(b) Hitung setiap yang berikut. telah membuat pengeluaran berjumlah
4
Calculate each of the following. RM ribu sebanyak 7 kali. Hitung purata
(i) 5 + (–6) – 1 (ii) –81 ÷ 9 × (–3) 5
[2 markah / 2 marks] simpanan Encik Wong dalam tempoh lima
Jawapan / Answer: tahun.
Mr. Wong saved RM1.3 thousand each month from
(i) 5 + (–6) – 1 = 5 – 6 – 1 his company profits for five years. Within that time, he
4
= –1 – 1 withdrew RM thousand for 7 times. Calculate Mr.
5
= –2 Wong's average savings in five years.
[3 markah / 3 marks]
(ii) –81 ÷ 9 × (–3) = –9 × (–3) Jawapan / Answer :
= 27 Purata simpanan / Average savings

4

2
= 1.3 × 12 × 5 – × 7 ÷ 5
(c) Alvin membeli beberapa guni buah durian = (78 – 5.6) ÷ 5 5
dengan harga RM800. Pada keesokan = 72.4 ÷ 5
harinya, dia menghadiahkan 5 biji durian = RM14.48 ribu / thousand
kepada jirannya dan 18 biji durian kepada
sepupunya. Jika Alvin menjual durian yang
tinggal dengan harga RM8.00 sebiji, dia akan (c) (i) Hitung / Calculate:
mendapat hasil jualan sebanyak RM512. –238 ÷ 7 – 4(42 – 54)
Berapa biji durian yang dibelinya pada [2 markah / 2 marks]
permulaan? Jawapan / Answer :
Alvin bought few bags of durians with the price of –238 ÷ 7 – 4(42 – 54)
RM800. On the next day, he gave 5 durians to his

neighbours and 18 durians to his cousins. If Alvin sells = –34 – 4(–12)
the remaining durians at RM8.00 each, he will get the = –34 + 48
total sales of RM512. How many durians did he bought = 14
at the beginning?
[3 markah / 3 marks]

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