Page 11 - Q & A STPM 2022 Physics
P. 11

Physics Semester 1  STPM  Chapter 1  Physical Quantities and Units
              Question 3

                                                       –1
                                                          –2
                                                   2
                                                     2
                The permittivity of free space e  has units A  s  N  m  and the permeability of
                                         0
                free space µ  has units N A . Their relationship is as shown in the equation below.
                                    –2
                         0                       1
                                           k  =
                                            2
                                                e µ 0
          Penerbitan Pelangi Sdn Bhd. All Rights Reserved.
                                                0
                Determine the appropriate unit for k.
                      –1
                                                   2
                A  m s  A                      C  m  s –2
                    2
                      –1
                B  m  s  A 2                   D  m s –1
              Answer: D     1        1       1      1
         Semester
                                                          2
         1       Unit for =   e µ 0   =   A s N m –2    NA –2   =  s m –2  = m  s –2
                                   2 2
                                      –1
                                                   2
                           0
                 Unit for k = m s –1
                1.2   Dimensions of Physical Quantities
               Section  A   Multiple-choice Questions
              Question 1
                The drag force F is related to the density ρ and velocity v by the equation
                                                  2
                                            F = kρv .
                Where k is a constant. The dimension of the constant k is
                A  M L 2                       C  L 2
                B  L T 2                       D  L –2

              Answer: C
                                       –3
                           –2
                 [F] = M L T    [ρ] = M L   [v] = L T –1
                 k =   F
                     ρv 2
                        M L T –2
                 [k] =           = L 2
                            2
                       ML  L  T –2
                         –3

                 Exam Tips
                 Exam Tips
                 Base quantities and their dimensions:
                 Mass (M), length (L), time (T), current (A), temperature (θ), quantity of matter (N).




                                               2




         01 STPM Q&A PHY T1.indd   2                                         17/02/2022   10:03 AM
   6   7   8   9   10   11   12   13   14   15   16