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Physics Semester 2  STPM  Chapter 14 Electric Current
              Answer:
                 (a)  Drift velocity is the average velocity of the electrons when they move
                     and collide with the positive ions in the opposite direction to the electric
                     field.
                 (b)
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                                         E
                         +             e             –
                        Z                 A
                                    Q     P
                                       v
                     Let  A = cross-sectional area
                        n = density of free electrons / number of electrons per unit volume
                        v = drift velocity
                     In one second, the electrons move from P to Q by a distance of v.
                     The volume from P to Q = Av
                     \  The total number of free electrons flowing from P to Q in 1 second
                       = nAv
                     The total charge flow from P to Q = nAve
                     \  Current flow = rate of flow of charge
                                 I = nAve
                                                            Exam Tips
                                                            Exam Tips
                 (c)  The number of charge carriers per unit
                     volume remains unchanged.                  Formulae used:
                     The drifts velocity increases as the increase   V = IR ρl
                     of  potential  difference  will increase the   R =   A
         Semester
         2           current flow in the conductor.             v =   I
                     v =   I  ,   V = IR                            nAe
                        nAe
                     The drift velocity is directly proportional to the current.


                 (d)  (i)   N   =   m
                         N A   M
                            N  =   mN A
                                M
                          N   =   mN A
                          V    VM

                             =  eN A
                                M
                               (8.93 × 10 )(6.02 × 10 )
                                       3
                                                23
                             =
                                    63.5 × 10 –3
                             = 8.466 × 10  atoms per m 3
                                       28
                                              226




         014 STPM Q&A Physics T2.indd   226                                  17/02/2022   10:12 AM
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