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Physics Semester 2  STPM  Chapter 14 Electric Current
              Question 3

                A charge of 60 Coulomb flows in a wire for 45 minutes. If the diameter of the
                wire is 1.0 mm, what is the current density in the wire?
                A  2.2 × 10  A m               C  7.6 × 10  A m –2
                             –2
                                                        7
                         4
                         4
                             –2
                B  2.8 × 10  A m               D  5.6 × 10  A m –2
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                                                        8
              Answer: B
                                                      Exam Tips
                     Q     60 C                       Exam Tips
                 I  =    =
                     t   45 × 60 s
                       = 2.222 × 10  C s –1           Unit of current is Ampere (A) or
                                 –2
                                                      Coulomb per second (C s ).
                                                                         –1
                 Area =  πd 2

                        4
                               –3 2
                      =  π(1 × 10 )
                            4
                      = 7.8540 × 10  m 2
                                 –7
                 Current density, J  =   I
                                  A
                                  2.222 × 10 –2
                                =
                                  7.854 × 10 –7
                                = 2.83 × 10  A m –2
                                         4
         Semester
         2    Question 4
                A current flows in a copper wire. The current density in the wire is 1.4 × 10
                                                                              6
                                                                   28
                A m . If the number of free electrons in 1 m  of wire is 8.4 × 10 , what is the
                                                    3
                   –2
                drift velocity of the electrons?
                          –4
                A  1.04 × 10  m s
                              –1
                B  3.10 × 10  m s –1
                          –4
                C  1.67 × 10  m s
                          –3
                              –1
                          –3
                D  1.90 × 10  m s –1
              Answer: A
                        J = nve
                   1.4 × 10  = (8.4 × 10 ) v (1.6 × 10 )
                        6
                                  28
                                             –19
                        v = 1.04 × 10  m s –1
                                   –4
                                              228




         014 STPM Q&A Physics T2.indd   228                                  17/02/2022   10:12 AM
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