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Physics Semester 3  STPM  Chapter 21 Sound Waves
              Question 15

                (a)  A string is stretched between two fixed points. The mid point of the string
                    is plucked and then released. Explain how a standing wave is set up in the
                    string.
                    Draw the fundamental mode of vibration of the standing wave.
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                (b)  A string fixed at both ends and having a mass of 4.80 g, a length of 2.00 m,
                    and a tension of 48.0 N vibrates in its second mode (n = 2).
                    (i)  What is the ratio of the wavelength in air of the sound emitted by this
                       vibrating string and the wavelength of the wave in the string?
                    (ii)  Find the three lowest frequencies of standing waves in the string?
                    (Speed of sound in air = 330 m s )
                                             –1

              Answer
                 (a)  After the string is plucked and released, pulses of wave travel along the
                     string toward the two fixed ends of the string where the wave pulses are
                     repeatedly reflected. Superposition of the reflected waves travelling in
                     opposite directions along the string produces the standing wave.




                     Fundamental mode

                 (b)

                                 L

                     (i)  Wavelength in string, λ = L = 2.00 m
                                             2   T
                             Frequency of sound, f =
                                             2L  μ
                                                      v
                         Wavelength of sound wave, λ sound  =     (v = speed of sound)
                                                      f
                                                          μ
                                                    =  vL  T
                                                                (4.80 × 10 /2.00)
                                                                        –3
                                                    =  (330)(2.00)            m
                                                                     48.0
                                                    =  4.67 m
                                  Wavelength of sound  4.67
                                                    =     = 2.34
                                  Wavelength in string  2.00
         Semester
         3




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         021 STPM Q&A Physics T3.indd   410                                  17/02/2022   10:24 AM
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