Page 15 - Get Ready SPM 2022 Tg 5 - Matematik

Kimia Tingkatan 5 Jawapan
Turn the coin during • Katod / Cathode:
Kertas 2
electroplating – Elektrod argentum
Bahagian A (Mana-mana dua /Any two) menebal dengan
1. (a) Tindak balas kimia yang Bahagian B pepejal kelabu.
melibatkan pengoksidaan dan Silver electrode thicken
with gray solid.
penurunan secara serentak. 3. (a) • Al, Ni, Ag – Nilai E argentum lebih
0
Chemical reaction where • Al ialah agen penurunan yang
0
oxidation and reduction occur paling kuat kerana nilai E paling positif berbanding 0
simultaneously. negatif dengan nilai E
0
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(b) +3 → 0 Al is the strongest reducing agent aluminium dan E
(c) Ferum(III) oksida//Ion ferum(III) because E value is the most hidrogen menyebabkan
0
Iron(III) oxide//Iron(III) ion negative. ion Ag + menerima
(d) Magnesium//Mg / Magnesium//Mg • Ag ialah agen penurunan yang elektron membentuk
(e) Mol ferum(III) oksida /Mole of paling lemah kerana nilai E 0 logam Ag.
0
iron(III) oxide paling positif. E value of silver is
more positive than E of
0
= 100 Ag is the weakest reducing agent aluminium and E value
0
0
160 because E value is the most +
= 0.625 positive. of hydrogen causing Ag
ion to accept electron to
1 mol ferum(III) oksida bertindak • Ni berada di antara Al dan Ag form Ag metal.
0
balas menghasilkan 2 mol ferum. kerana nilai E berada di antara • Agen pengoksidaan/
0
1 mole of iron(III) oxide reacts to dua nilai E . Oxidising agent: Ag +
produce 2 moles of iron. Ni is in between Al and Ag Agen penurunan/Reducing
0
\ 0.625 mol ferum(III) oksida because the E value is in between agent: Al
0
the two E values.
bertindak balas menghasilkan (b) • Pasangan logam Ni/Al:
1.25 mol ferum Bahagian C
\ 0.625 mole of iron(III) oxide Ni/Al metal pair:
0

E Sel/E Cell = ‒0.25 – (‒2.38)
0
reacts to produce 1.25 moles of = 2.13 V 4. (a) (i) X = Ferum//Iron//Fe/Ferum//
iron. Besi//Fe
Jisim ferum/Mass of iron • Pasangan logam Al/Ag: 2Fe 2 O 3 + 3C → 4Fe + 3CO 2
= 1.25 × 56 Al/Ag metal pair: (ii) • Fe 2 O 3 mengalami
0
E Sel/E Cell = 0.80 – (‒2.38)
0
= 70 g = 3.18 V penurunan kerana ferum
2. (a) (i) Tindak balas redoks yang (c) (i) kehilangan oksigen
melibatkan logam dioksidakan menghasilkan atom Fe.
secara spontan apabila V Fe 2 O 3 undergoes reduction
atom logam membebaskan because iron loses oxygen
elektron membentuk ion producing Fe atom.
logam. – + Argentum • C mengalami
Redox reaction where Aluminium (katod) pengoksidaan kerana
the metal is oxidised (anod) Silver (cathode) karbon menerima oksigen
spontaneously when the metal Aluminium menghasilkan CO 2 .
atoms release electrons to (anode) Larutan argentum C undergoes oxidation
form metal ions. nitrat (elektrolit) because carbon receives
(ii) Kuprum/Copper Silver nitrate solution oxygen producing CO 2 .
(electrolyte)
(iii) Ion kuprum(II)//Cu 2+ (b) • Prosedur dan pemerhatian:
Copper(II) ion//Cu 2+ Procedure and observation:
3
(b) (i) (ii) • Setengah persamaan 1. Tuangkan 200 cm larutan
di anod /Half-equation at kuprum(II) sulfat 1.0 mol dm
–3
anode: Al → Al + 3e ‒ ke dalam bikar.
3+
Setengah persamaan di Pour 200 cm of 1.0 mol dm
–3
3
Syiling katod / Half-equation at
Argentum Coin cathode: Ag + e → Ag copper(II) sulphate solution into
‒
+
(anod) • Anod/Anode: a beaker.
Silver (anode) Larutan argentum 2. Sambungkan kuprum tulen
nitrat (elektrolit) – Elektrod aluminium kepada terminal negatif
Silver nitrate solution menipis. bateri dan kuprum tidak
(electrolyte) Aluminium electrode tulen kepada terminal positif
(ii) • Syiling dibersihkan becomes thinner. bateri.
menggunakan kertas – Nilai E 0 aluminium Connect pure copper to the
pasir. yang lebih negatif negative terminal of the battery
Coin is cleaned using berbanding dengan and impure copper to the
sandpaper. nilai E 0 argentum positive terminal of the battery.
• Menggunakan voltan menyebabkannya 3. Lengkapkan litar.
yang lebih rendah. menderma elektron Complete the circuit.
Use a lower voltage. untuk membentuk ion 4. Biarkan selama 30 minit.
3+
• Menggunakan kepekatan Al . Leave it for 30 minutes.
0
larutan argentum nitrat E value of aluminium 5. Selepas 30 minit, kuprum
yang lebih rendah. is more negative than tulen akan menebal dan
0
Use a lower concentration E value of silver which kuprum tak tulen akan
of silver nitrate solution. causes it to release menipis.
3+
• Memutar-mut arkan electrons to form Al After 30 minutes, pure copper
syiling semasa proses ions. becomes thicker while impure
penyaduran sedang copper becomes thinner.
berlaku.
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