Page 56 - Pra U STPM 2022 Penggal 3 - Maths (T)
P. 56

Mathematics Semester 3  STPM  Chapter 5 Hypothesis Testing

                                        Step 4 : Calculate the value of the test statistic.
                                                              –
                                                              x – µ    39.4 – 38
                                                          z =   σ    =    6.8    = 2.058
                                                                n
                                                                       
                                                                          100
                                        Step 5 : Make a decision.
                                        To make a decision, we compare the value of the test statistic to the critical
                                        value. This value of z = 2.058 is greater than the critical value of 1.96 and thus
                                        it falls in the critical region. We reject H  and conclude that the mean length of
                       Penerbitan Pelangi Sdn Bhd. All Rights Reserved.
                                                                         0
                                        the iron nails produced by the manufacturer does not meet the target length of
                                        38 mm.
                  Note:  Example 6: Large sample, known population variance.


                  Population mean, variance unknown
                                                 2
                  In practice, the population variance σ is usually not known. However as long as the sample size is large, the
                                                       –
                  normal approximation for the sample mean X remains valid even if s is replaced by its unbiased estimate
                                                                                 –
                  ^                                                              X – µ   .
                  σ. We can then apply the general test procedure using the test statistic Z =
                                                                                   ^
                                                                                   σ
                                                                                   n
                                                                                  
                                                                            n
                                         2
                  Note : σ  =   n   s  where s  is the sample variance given by s  =   1   ∑  (x – x) .
                                                                     2
                                 2
                       ^  2
                                                                                  – 2
                            n – 1                                        n i = 1
                      Example 7
                   A sample of 60 watches of a particular brand is checked for accuracy at 10:00:00 hours. Let μ denote the
                   true mean watch reading when the actual time is 10:00:00 hours. The resulting sample mean and sample
                   standard deviation are  10:00:01.2 hours and 1.8  seconds respectively.  Use a  significance  level  of 1% to
                   decide whether the evidence from the sample suggests the watches are fast.
                                           –
                   Solution:            Let x be the mean watch reading for the sample. Given information: μ = 10:00:00
                                                                  –
                                        hours, s = 1.8 seconds, n = 60, x = 10:00:01.2 hours.
                                                                 2
                                        ^
                                        s  is calculated as s  =     n   s
                                                      ^
                                                            n – 1
                                                        =   60  × 1.8 2                                      5
                                                            59
                                                        = 1.815 seconds
                                        We are going to test whether the mean watch reading is fast. The significance
                                        level a is 0.01.
                                        We carry out a hypothesis test using the following five steps.
                                        Step 1 : State the null hypothesis and the alternative hypothesis.
                                        H  : μ = 10:00:00 hours,
                                         0
                                        H  : μ . 10:00:00 hours.
                                         1
                                        Step 2 : Specify the significance level.
                                        a = 0.01.
                                        Step 3 : Select an appropriate probability distribution and determine the critical
                                        region.



                                                                                                      247






         05 STPM Math(T) T3.indd   247                                                                28/10/2021   10:24 AM
   51   52   53   54   55   56   57   58   59   60   61