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Mathematics Semester 3  STPM  Chapter 5 Hypothesis Testing

                                     The population standard deviation is not known and the sample size is large.
                                     We will use the normal distribution to perform the test.
                                     This  is  a  one-tailed  test  with  a  critical  region  at  the  right  tail.  To  locate  the  z
                                     value, we look for 0.01 area in the normal distribution table. From the table, the
                                     z value is approximately 2.33.
                                     The critical region: z . 2.33.
                                     Step 4 : Calculate the value of the test statistic.
                                                             –
                                                             x – µ
                                                         z =       =   1.2 – 0   = 5.122
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                                                               σ ^    1.815
                                                               n
                                                                     
                                                                       60
                                     Step 5 : Make a decision.
                                     To make a decision, we compare the value of the test statistic to the critical
                                     value. This value of z = 5.122 is greater than the critical value of 2.33 and thus
                                     it falls in the critical region. We reject  H  and conclude that the true average
                                                                       0
                                     watch reading is faster than the actual time of 10:00:00 hours.


               Relationship between hypothesis tests and confidence intervals

               The hypothesis testing is very closely related to the estimation by a confidence interval. For the case of a
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               normal population with unknown mean μ and known σ , both hypothesis testing and confidence interval
                                                         –
               estimation are based on the random variable, z =   X – µ   . It turns out that the testing of H  : μ = μ  against
                                                           σ
                                                                                                0
                                                                                          0
                                                          
                                                           n
               H  : μ ≠ μ  at a significance level a is similar to calculating a 100(1 – a)% confidence interval for μ. If µ
                                                                                                       0
                 1
                        0
               is outside the 100(1 – a)% confidence interval, then H is rejected at a, and if μ  is inside the 100(1 – a)%
                                                            0
                                                                                 0
               confidence interval, then H  is not rejected at a.
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                    Exercise 5.2
                 1.  Determine the critical region and the critical values for z at a = 0.02 in the hypothesis testing:
                                              H  : μ = 50 against H  : μ , 50.
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           5     2.  Find the critical values x given that H  : μ = 850, H : μ ≠ 850, σ = 36, n = 80. Use a = 0.05.
                                        –
                                                    0          1
                                                             –
                 3.  Given that H  : μ = 250, H  : μ ≠ 250 with n = 80, x = 248, σ = 10.7. State whether the null hypothesis
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                               0
                    H  should or should not be rejected at a = 0.02.
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                 4.  For the hypothesis test  H  :  μ  = 16.8,  H  :  µ  . 16.8, what is your conclusion at  a = 0.1 if  n = 45,
                    –                    0            1
                    x = 17.5, s = 2.5?
                 5.  In a random sample of 20 observations from a normal distributed population with standard deviation
                                             –
                    s = 27.6, the sample mean is x = 110. Use a = 0.01 to perform the following hypothesis test:
                                                H  : μ = 120, H  : μ , 120.
                                                  0          1
                    Next, change the sample size to 200 and perform the test again. Explain why you make different
                    decisions as the sample size increases.




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         05 STPM Math(T) T3.indd   248                                                                28/10/2021   10:24 AM
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