Page 18 - Praktis Hebat PT3 2022 - Tg 2 Matematik

JAWAPAN

PRAKTIS PT3 Pola dan Jujukan Bahagian C
1
Patterns and Sequences
Penerbitan Pelangi Sdn Bhd. All Rights Reserved.
1. (a) (i) Darab nombor sebelumnya dengan 3.
Multiply the previous number by 3.
Bahagian A (ii) Tolak 6 daripada nombor sebelumnya.
Subtract 6 from the previous number.
1. C 2. A 3. D 4. B 5. B (iii) Tambah 5 kepada nombor sebelumnya.
6. C 7. D 8. D 9. B 10. A Add 5 to the previous number.
(b) –102
Bahagian B
(c) (i) 5
(ii) 20
1.
16 20 2. (a) (i) Nombor ganjil / Odd numbers:
11, 21, 31, 41, 51, 61
20 Pola: Menambah 10 kepada nombor
P 12 Q 28 sebelumnya.
Pattern: Add 10 to the previous number.
Nombor genap / Even numbers:
8 4 16, 26, 36, 46, 56
4 –4 Pola: Menambah 10 kepada nombor
sebelumnya.
2. (a) 233; 610 Pattern: Add 10 to the previous number.
(b) (i) ✗ (b) (i) Jujukan / A sequence
(ii) ✓ (ii) Bukan jujukan / Not a sequence
(iii) Bukan jujukan / Not a sequence
3. (a) 121; 191
(b) (i) Tolak 25 daripada nombor sebelumnya. (c) 2.4 + 1.6n, n = 1, 2, 3, …
Subtract 25 from the previous number. 3. (a) (i) 1, 4, 9, …
(ii) Darab nombor sebelumnya dengan −4. (ii) T = n , n = 1, 2, 3, …
2
n
Multiply the previous number by −4. (iii) 144
4. (b) (i) 45 − 6n, n = 0, 1, 2, 3, …
1 (ii) −30
(c) P = 50; Q = 68; R = 74
1 1
4. (a) (i) P = −3.36; Q = −0.24
1 2 1 (ii) a = 61; b = 85
(b) 10
1 3 3 1
(c) 36
 
1 4 6 4 1 5. (a) (i) 1 1 n , n = 0, 1, 2, 3, …
4 2
(ii) 43 − 5n, n = 0, 1, 2, 3, …
1 5 10 10 5 1
(iii) 6n + 16, n = 0, 1, 2, 3, …
(b) (i) +6
5. (ii) −96
–1, 3, 7, 11, ... 3 + 3n (c) 10, 12.4, 14.8, 17.2, 19.6, 22, …
+2.4 +2.4 +2.4 +2.4 +2.4
6, 9, 12, 15, ... 7 × 2 n 10 + 12.4 + 14.8 + 17.2 + 19.6 + 22 = 96
96  100
Ya. Reben berukuran 1 meter tersebut cukup
14, 28, 56, 112, ... 4n – 5
panjang untuk dipotong kepada 6 bahagian.
Yes. The 1 metre ribbon is long enough to be cut
3 , 3 , 3 , 3 3 into 6 parts.
5 25 125 625 5 n

J1 © Penerbitan Pelangi Sdn. Bhd.

15 JAW Praktis HEBAT Mate Tg2.indd 1 18/02/2022 3:40 PM