Page 19 - Praktis Hebat PT3 2022 - Tg 2 Matematik
P. 19
Matematik Tingkatan 2 Jawapan
KBAT (c) 20p + 500
2. (a) (i) 10y − 19y + 6
2
42 (ii) 5klm
17p + 24q 2
PRAKTIS PT3 Pemfaktoran dan Pecahan Algebra (b) 2 q 2
2
Factorisation and Algebraic Fractions
(c) (5x + 10x + 4) cm
3. (a) 1, 3 dan / and f
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Bahagian A (b) 4
a + 4
1. D 2. B 3. D 4. A 5. C (c) 9x 2 + 21x − 9 cm 2
6. C 7. D 8. D 9. A 10. C 8 4
4. (a) (4x + 5y − 3)(4x − 5y − 13)
Bahagian B a
(b)
1. (a) ✗ (b) ✓ (c) ✗ (d) ✓ b(a + 1)
2
2. (a) (c) (2a + 10a + 12) cm 2
9 5. (a) (i) −6p + 4q
2
(ii) −3j + 9j
3 9p (iii) m n − 2m 2
2
9p, (b) b − 7b −1
2
18pq (c) 6
p 3p
1 KBAT
(a) Panjang dan lebar segi empat tepat Q ialah 2h kali
(b) panjang dan lebar segi empat tepat P.
2x 1 x
The length and width of rectangle Q is 2h times the length
x –6 –12x and width of rectangle P.
(b) Jika panjang dan lebar segi empat tepat Q ialah 2h kali
2x 2 –6 –11x panjang dan lebar segi empat tepat P, maka luas segi
2
empat tepat Q ialah 4h kali luas segi empat tepat P.
3. (a) 4gh – 8h 2 4gh(1 – 2h) If the length and width of rectangle Q is 2h times the
length and width of rectangle P, then the area of rectangle
Q is 4h times the area of rectangle P.
2
2
4gh – 8gh 2 4h(g – h )
PRAKTIS PT3
4gh – 4h 3 4h(g – 2h) Rumus Algebra
3
2
(b) 14m + 21m = 7m (2 + 3m) Algebraic Formulae
2pq + 4q 6pq Bahagian A
4. ÷
9 – q 2 3 – q
1. A 2. D 3. C 4. C 5. A
2q (p + 2) 3 – q 6. B 7. B 8. A 9. A 10. D
= × 6pq 11. D
(3 – q) (3 + q)
p + 2 Bahagian B
=
3p(3 + q) 1. (a)
q = p – 3
2
Bahagian C p = 2q + 3
1. (a) (i) (a) 4pq − 12p q = 2(p + 3)
(b) −18 + 24p
(ii) (2y − 3)(5y + 4) q
m + 6m n p = – 3 p – 3
2 3
(b) (i) 2 q =
2n 2
3
x + 2x + y 2
2
(ii) (b) (i) 3 (ii) 2
x + 2x
2
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15 JAW Praktis HEBAT Mate Tg2.indd 2 18/02/2022 3:40 PM

