Page 42 - Hybrid PBD Matematik TG3_Edisi Guru

Matematik Tingkatan 3 Bab 2
11. Tukarkan ukuran dalam sistem metrik berikut kepada unit yang diberikan dalam kurungan. Nyatakan jawapan
anda dalam bentuk piawai. SP 2.2.1 TP3
Change the following metric measurements to the units given in the brackets. State your answers in standard form.

(a) 2 310 gigabait [bait] (b) 323 milimeter [meter]
0.0018 attoliter [liter] 2 310 gigabytes [byte] 323 millimetres [metre]
0.0018 attolitre [litre]
= 2.31 × 10 × 10 = 3.23 × 10 × 10 –3
3
2
9
= 0.0018 × 10 1 atto = 10 –18 = 2.31 × 10 3 + 9 = 3.23 × 10 2 + (–3)
–18
= 1.8 × 10 × 10 = 2.31 × 10 bait/ bytes = 3.23 × 10 meter/ metre
–3
–18
12
–1
= 1.8 × 10 –3 + (–18) a × a = a m + n
n
m
–21
= 1.8 × 10 liter/ litre (c) 0.045 desimeter [meter] (d) 0.543 petaliter [liter]
0.045 decimetre [metre] 0.543 petalitre [litre]
123 123
+ + x x
1 1 2 2 Guna Kalkulator
3 3 4 4 = =
–1
–2
15
Tekan/ Press = 4.5 × 10 × 10 –1 = 5.43 × 10 × 10
0 · 0 0 1 8 = 4.5 × 10 –2 + (–1) = 5.43 × 10 –1 + 15
EXP (–) 1 8 = = 4.5 × 10 meter/ metre = 5.43 × 10 liter/ litre
14
–3

12. Hitung nilai yang berikut dan ungkapkan jawapan dalam bentuk piawai. SP 2.2.2 TP4
Calculate the values of the following and express your answers in standard form.
(i) 2.3 × 10 – 1.83 × 10 Bagi operasi + dan –, tulis semula kuasa
3
2
= 2.3 × 10 – 0.183 × 10 × 10 bagi asas 10 untuk menyamakan indeks. Tip Penting
1
3
2
For operations + and –, rewrite the powers of 10
3
3
= 2.3 × 10 – 0.183 × 10 so that they have the same index. a × 10 + b × 10 = (a + b) × 10
n
n
n
n
n
n
= (2.3 – 0.183) × 10 Faktorkan 10 3 a × 10 – b × 10 = (a – b) × 10
3
3
= 2.117 × 10 Factorise 10 a × 10 × b × 10 = (a × b) × 10 m + n
n
m
3
a
m – n
n
m
b
(ii) 3.04 × 10 2 = 3.04 × 10 2 – (–1) Hukum indeks a × 10 ÷ (b × 10 ) = × 10
0.8 × 10 0.8 Law of indices
–1
= 3.8 × 10
3
4
3
–5
(a) 3.4 × 10 + 6.1 × 10 (b) 8.9 × 10 – 1.2 × 10 3 (c) 1.98 × 10 – 1.08 × 10
4
–5
= (3.4 + 6.1) × 10 = (8.9 – 1.2) × 10 = (1.98 – 1.08) × 10
3
–5
4
= 9.5 × 10 = 7.7 × 10 = 0.9 × 10 9 × 10 × 10 –5
3
–5
4
–1
= 9 × 10 –6
(d) 9.3 × 10 + 2.13 × 10 (e) 4.05 × 10 – 2.2 × 10 (f) 2.4 × 10 × 1.8 × 10
7
–5
–8
–7
–4
–3
–4
–7
–7
–4
= 0.93 × 10 + 2.13 × 10 = 4.05 × 10 – 0.22 × 10 = 2.4 × 1.8 × 10 7 + (–3)
= (0.93 + 2.13) × 10 = (4.05 – 0.22) × 10 = 4.32 × 10 4
–7
–4
= 3.06 × 10 = 3.83 × 10
–4
–7
(g) 7 200 000 × 1.5 × 10 (h) 1.2 × 10 ÷ (6 × 10 ) (i) 7.9 × 10 × 2.1 × 10
2
5
–4
5
–4
= 7.2 × 10 × 1.5 × 10 = 1.2 × 10 5 – 5 = 7.9 × 2.1 × 10 2 + (–4)
6
–4
= 7.2 × 1.5 × 10 6 + (–4) 6 = 16.59 × 10
–2
–2
2
= 10.8 × 10 1.08 × 10 × 10 2 = 0.2 × 10 10 = 1 = 1.659 × 10 × 10
0
0
= 1.08 × 10 = 2 × 10 –1 = 1.659 × 10
–1
3
1.8 × 10 –9 4 800 6.3 × 10 –5
(j) (k) (l)
5 × 10 8 2.5 × 10 6 12 000
1.8 10 –9 4.8 × 10 3 6.3 × 10 –5
= × = =
5 10 8 2.5 × 10 6 1.2 × 10 4
= 0.36 × 10 –9 – 8 = 4.8 × 10 3 – 6 = 6.3 × 10 –5 – 4
= 3.6 × 10 × 10 2.5 1.2
–17
–1
–9
–3
= 3.6 × 10 = 1.92 × 10 = 5.25 × 10
–18
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02_ Hybrid Mate Tg3.indd 18 20/08/2021 5:28 PM