Page 29 - The Effect of Hydrogen and Hydrides - ebook first test
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
                      ′  
                                      2
                  −∆     ℎ      = 1.584 × 10  J m −3
                                
                                  ∆      ∗
                                                               ∆      ∗



                                          
                                                                                    ̅   
                                                                                 ∗             




                            ′  
                        −∆     ℎ                                

                  Table 3-1:   Enthalpies of dissolution and formation for TSSD, TSSP1 and TSSP2 derived from a fit of the experimental
                             data of Pan and co-workers [Pan et al., 1996] assuming a common value for the pre-exponential term,
                                            4
                                = 3.9153 × 10  wppm. The corresponding value for TSSE was derived assuming ∆   =
                                                                                                 
                             −√∆     2  ∙ ∆   .
                                           
                         Hydride Solubility Expressions (wppm)    Enthalpies in Solubility Expressions (J mol  H)
                                                                                                     1

                                                 ⁄
                              
                              (        ) =     ∙ exp(∆          )             ∆   = −31 000
                              
                                                                                   
                              
                              (        1) =    ∙ exp(∆   ⁄     )              ∆     1  = −27 7040
                                                  1
                             
                              
                              (        2) =    ∙ exp(∆   ⁄     )              ∆     2  = −28 942
                                                  2
                             
                              (        ) =     ∙ exp(∆   ⁄     )              ∆   = −29 953
                              
                              
                                                  
                                                                                   
                                                                                           © ANT International 2018
                                                                                     −3 −1
                                                                            20
                                                                       ≈ 10  nuclei m s
                                              −3
                                    = 5.85 × 10  J m −2
                                    

                                                                            1 × 10 −6
                                                                   −3
                                                            3.8 × 10  J m −2
                                                           20
                                                                    −3 −1
                                                       ≈ 10  nuclei m s










                                                              
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