Page 157 - SK Year 5 Mathematics DLP

Centuries and decades

1
1
1 Cave A is 6 centuries old. 6 centuries + 3 centuries = centuries
1
5 5 2
1
Cave B is 3 centuries older
1
1
2 6 centuries + 3 centuries
than Cave A. 5 2
1 × 2 1 × 5
= 6 centuries + 3 centuries
5 × 2 2 × 5
2 5
The age of = 6 centuries + 3 centuries
10
10
Cave B is ... 7
= 9 centuries
10
1 1 7
6 centuries + 3 centuries = 9 centuries
5 2 10

3
2 century + 29 decades = decades
10
1
3 3 3 decades
10 century = ( 10 × 10) decades + 29 decades
= 3 decades
32 decades

3
10 century + 29 decades = 32 decades

4
3 2 centuries + 8 centuries 7 decades = centuries decades
5

century decade
4 4
2 centuries = 2 centuries + century 2 8
5 5
4 2 + 8 7
= 2 centuries + ( × 10) decades 1 0 1 5
5
1 + 1 − 1 0
= 2 centuries 8 decades 1 1 5
4
2 centuries + 8 centuries 7 decades = 11 centuries 5 decades
5

State 11 centuries 5 decades in decades.

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4.3.1 (v)