Page 48 - Math 7
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Operations on Whole Numbers

           Example 4: Simplify  a)   8   × 2 18  × 3 75    (b)   144
                                                                441
           Solution:
           a)   8  × 2 18 × 3 75
                                                      Think of the factors of 8, 18 and 75 such
                = 4 × 2 × 2 9 × 2 × 3 25 × 3          that one of the factors is a perfect square.


                = 2 2 × 2 × 3 2 × 3 × 5 3       Find the square root of each perfect square factor.

                = 180 12      2 × 6 × 15 = 180 and  2 ×  2 ×  3 =  12


                = 180 × 4 × 3       Think  of the factors of 12 such that one of
                                    the factors is a perfect square.
                = 180 u 2 3
                = 360 3
                                                              144  = 2 × 2 × 2 × 2 × 3 × 3
                                                                      2
                                                                           2
                           2
                                2
           b)   144  =    2  × 2  × 3 2                            = 2  × 2  × 3 2
                              2
                                   2
               441          3  × 7                            441  =  3 × 3 × 7 × 7
                                                                      2
                     =  2 × 2  =  4                                = 3  × 7 2
                         7       7
           Example 5:  Find the square root of 3.24
           Solution:
                                                               2 324     2 100
            Here,  3.24 =  324                                 2 162     2 50
                           100
                                                               3 81      5 25
            ?       3.24  =   324                              3 27         5
                            100
                                                               3 9
                            2  × 3 × 3 2                          3
                             2
                                  2
                        =      2  × 5 2              324 = 2 × 2 × 3 × 3 × 3 × 3
                               2
                                                              2
                                                                  2
                        =  2 × 3 × 3                       = 2  × 3  × 3 2
                              2 × 5                   100  = 2 × 2 × 5 × 5
                                                              2
                        =  18  = 1.8                       = 2  × 5 2
                           10
           Example 6 : There are 40 pupils in class 7. If every pupil collects as much as
                        money as their numbers for a charity show, how much money do
                        they collect altogether?
           Solution:
           Here,  Number of pupils = 40
                   sum of money collected from each pupil = Rs 40
           Thus,   the required sum of money                = Rs (40 )
                                                                     2
                                                            = Rs ( 40 × 40) = Rs 1600.
           Hence, they collect Rs 1,600 altogether.

           Vedanta Excel in Mathematics - Book 7   46    Approved by Curriculum Development Centre, Sanothimi, Bhaktapur
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