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210                                                                                    PHYSICS

                         Energy                                             Power
                         1 kW h = 3.6 MJ                                    1 horsepower (hp) = 550 ft lbf/s
                         1 cal = 4.186 J                                                = 745.7 W
                                                                                     –1
                         1ft lbf = 1.356 J = 1.286 × 10 –3  Btu             1 Btu min  = 17.58 W
                                                                                            –3
                         1 L atm = 101.325 J                                1 W = 1.341 × 10   hp
                         1 L atm = 24.217 cal                                      =  0.7376 ft lbf/s
                         1 Btu = 778 ft lb = 252 cal = 1054.35 J            Thermal Conductivity
                                                                                  –1  –1
                                                                                                         2
                         1 eV = 1.602 × 10 –19 J                            1 W m K  = 6.938 Btu in/hft  °F

                              2
                                                                                       2
                         1 u c  = 931.50 MeV                                1 Btu in/hft  °F = 0.1441 W/m K
                                   –7
                         1 erg = 10 J
                                                              APPENDIX   A 5
                                                        MATHEMATICAL FORMULAE
                         Geometry                                                        y           x
                                                                                  sin θ =          cos θ =
                         Circle of radius r: circumference = 2πr;                        r           r
                         area = πr 2                                              tan θ =  y         cot θ =  x
                                                      2
                         Sphere of radius r: area = 4πr ;                                x           y
                                                                                         r           r
                                   4                                              sec θ =          csc θ =
                         volume =  π r 3                                                 x           y
                                   3
                         Right circular cylinder of radius r            Pythagorean Theorem
                                                      2
                         and height h: area = 2π r +2π r h;
                                                                                                   2
                                                                                              2
                                                                        In this right triangle, a  + b  = c 2
                         volume = rπ  2 h ;
                         Triangle of base a and altitude h.
                                1
                         area =    a h
                                2
                         Quadratic Formula
                               2
                         If    ax  + bx + c = 0,
                                            2
                                    −  b ±  b −  4ac
                         then    x =
                                            a 2
                         Trigonometric Functions of Angle θθ θθ θ                        Fig. A 5.2
                                                                        Triangles
                                                                                Angles are A, B, C

                                                                                Opposite sides are a, b, c
                                                                                Angles A + B + C = 180 0

                                                                                sin A  sin B  sin C
                                                                                     =      =
                                                                                  a     b      c
                                                                                 2   2   2
                                                                                c  = a + b  – 2ab  cos C
                                        Fig. A 5.1                              Exterior angle D = A + C









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