Cq>aQ(A)d+Q(B)dp
Q(C)dR2J(A)J(B)$)Q(:)
q>aJ(A)d+J(C)dpJ(B)
dR2J(A)J(C)$)Q(:)
q>aJ(B)d+J(C)dpJ(A)
dR2J(B)J(C)$)Q
To calculate the angles, A = 12.7279, B = 12.0416 and
C = 10.4403.
r
A? 12.7279=
B? 12.0416=
C? 10.4403=x
=x =x
o
When these are added you will get 180 as expected.
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