Page 25 - Integration Problems
P. 25
Example 5:
Perform the integration
2
2
∫
1 +
1
Make the substitution,
= 1 +
Then
= , or =
The integral becomes,
2
2 2 2 2
∫ = ∫ . = ∫
1 + 1 1
1
Since = 1 + , then = − 1
The integral becomes,
2 − 1
∫
1
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