Page 26 - More Higher algebra
P. 26
Examples 5:
Finding solutions to logarithmic problems.
1.
= 2 log ( ) + 3
4
Find the value of x which gives y = 0; make x the
subject.
2 log ( ) = −3
4
Divide both sides by 2
3 3
log ( ) = − = − log (4)
4
4
2 2
This becomes,
3
−
log ( ) = log (4) 2
4
4
Remove the logs,
1
=
√4 3
Keystrokes for your fx calculator,
1as4q(x )=n
3
22

