Page 7 - MEKMUK-converted
P. 7

SKEMA JAWAPAN


               Soalan 1:




























               Sudut dongakan titik J dari titik M = ∠KMJ


               Soalan 2:























               JN = 10 tan 42  = 9.004 m
                                o
               NM = 25 – 9.004 = 15.996 m
               KL = NM = 15.996 m

               tan∠KML=KL/ML
               =15.996/10
               =1.5996
               ∠KML=tan−1 1.5996
               =57o59‘



                                                                       NAJMI,LUQMAN,TAQIUDDIN,WAHBAH
   2   3   4   5   6   7   8   9   10   11