Page 21 - Modul A+1 Kimia Tingkatan 5

(ii) H (c) C H + 19 O → 6CO + 7H O [1]
2
2
6
14
2
2
H C H Jisim molar/ Molar mass = 6(12) + 14(1) = 86 [1]
8.6
H H H H H H Bilangan mol/ Number of moles, n = 86 = 0.1 [1]
1 mol C H → 6 mol CO
H C C C C H H C C C H 6 14 2
1 mole of C H → 6 moles of CO 2
14
6
H H H H H H H 0.1 mol C H → 0.6 mol CO 2
6
14
0.1 mole of C H → 0.6 moles of CO
2-butena 2-metilpropena 6 14 3 2
2-butene 2-methylpropene = 0.6 × 24 = 14.4 dm [1]
[4]
(iii) 1. 2 cm larutan kalium manganat(VII), KMnO Kertas 3/ Paper 3
3
4
berasid dituang ke dalam dua tabung uji. 1.
2 cm of acidified potassium manganate(VII),
3
KMnO solution is poured into two test tubes. Pemerhatian/ Observation
4
2. Kedua-dua gas dialirkan ke dalam tabung Eksperimen Sebatian organik P Sebatian organik Q
uji yang mengandungi larutan kalium Experiment Organic compound P Organic compound Q
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manganata(VII), KMnO 4 berasid secara
berasingan. Perang kepada
Both gases is flowed into separate test tubes I tidak berwarna Tiada perubahan
containing acidified potassium manganate(VII), Brown to colourless No change
KMnO solution.
4
3. Warna ungu larutan akan dinyahwarnakan oleh Ungu kepada
gas P. Tiada perubahan
The purple colour of the solution will be II tidak berwarna No change
decolourised by gas P. Purple to colourless
4. Gas Q tidak memberi kesan kepada warna ungu [4]
larutan. (a) (i) Sebatian Q/ Compound Q [2]
Gas Q have no reaction with the purple colour (ii) Sebatian P/ Compound P
of the solution. [4] (b) (i) Heksena/ Hexene [2]
(ii) Heksana/ Hexane
(b) (i) C H OH + 2[O] → C H COOH + H O [1] (c) (i) 1, 2-dibromoheksana/ 1, 2-dibromohexane [2]
9
7
2
4
3
Pengesteran/ Esterification [1] (ii) Heksan-1, 2- diol/ Hexan-1, 2-diol
(d) Tindak balas penambahan/ Addition reaction [1]
H
CH CH CH C O CH CH CH CH
3 2 2 2 2 2 3 BAB 3
Butil butanoat/ Butyl butanoate [2+1]
(ii) C H + 6O → 4CO + 4H O [1] Soalan Berformat SPM
4 8 2 4(12) 2 2
% C = 4(12) + 8(1) × 100% [1] Kertas 1/ Paper 1
= 85.7 % [1] 1. B 2. C 3. C 4. B 5. B
6. C 7. A 8. C 9. D 10. C
Bahagian C/ Section C
4. (a) Kertas 2/ Paper 2
Kumpulan Formula Bahagian A/ Section A
Formula am
Sebatian General berfungsi struktur Nama 1. (a) Eksotermik. Membebaskan haba ke persekitaran kerana
Compound Functional Structural Name ΔH mempunyai tanda negatif.
formula Exothermic. Released heat to surrounding because ΔH
group formula
has a negative sign. [2]
H H H Propanol (b) Ikatan kovalen H–H dan ikatan kovalen Cl–Cl./ Covalent
A C H 2n+1 OH –OH H C O C H C H H Propanol bond H–H and covalent bond Cl–Cl. [2]
n
H (c) Jumlah kandungan tenaga bahan tindak balas lebih tinggi
berbanding jumlah kandungan tenaga hasil tindak balas
Total energy content of the reactants is higher than total
H H H Propena
B C H C=C H C C C H energy content of the products. [2]
n 2n Propene
H 2. (a) Haba yang dibebaskan apabila 1 mol kuprum, Cu
disesarkan daripada larutan kuprum(II) sulfat, CuSO oleh
Asid zink, Zn. 4
H H O propanoik Heat released when 1 mole of copper, Cu is displaced from
C C H 2n+1 COOH –COOH H C C C OH Propanoic copper(II) sulphate, CuSO solution by zinc, Zn. [1]
n
H H (b) Eksotermik/ Exothermic 4 [1]
acid
(c) (i) θ = mcθ
(b) = 50 × 4.2 × 8
Serpihan porselain Propena = 1680 J
Porcelain chips Propene
= 1.68 kJ [1]
(ii) Bilangan mol CuSO / Number of moles of CuSO 4
4
= mv = 0.01
Panaskan 1000
Heat = 0.2 × 50 = 0.01 mol
Wul kaca direndam Air 1000
dalam propanol Water [3] Haba penyesaran/ Heat of displacement
Glass wool soaked = 0.01 mol = –168 kJ mol [2]
1.68 kJ
in propanol
–1
Jawapan C H OH → C H + H O [1] (d) Zn + CuSO → ZnSO + Cu ∆H = –168.0 kJ mol [1]
–1
4
4
2
3
3
7
6
MG-12