Page 15 - Matematik Tam_Modul A+_Pan Asia Publications

Uji Kendiri 1.4

1. Rajah menunjukkan sebuah bulatan berjejari 6.5 cm 2. Rajah menunjukkan sepotong tembikai dengan keratan
dan berpusat O. Diberi bahawa AB adalah sama panjang sektor berpusat O.
dengan AC. The diagram shows a piece of water melon in a shape of a
The diagram shows a circle with a radius of 6.5 cm and sector with centre O.
centre O. Given that the length of AB is the same as AC.
O 10 cm
B
q
D
C
O 2 cm 16 cm
A B
50°
A C 20 cm
Diberi bahawa panjang lengkok AB dan CD masing-
Cari / Find masing ialah 20 cm dan 16 cm dengan bahagian ABCD
(a) perimeter rantau berlorek, tidak boleh dimakan. Jika AC = 2 cm dan panjang
the perimeter of the shaded region, potongan tembikai itu ialah 10 cm, cari
(b) luas rantau berlorek itu. Given that the arc length of AB and CD is 20 cm and 16 cm
the area of the shaded region. KBAT Menilai respectively with the portion ABCD is not edible. If AC = 2 cm
and the length of a piece of the water melon is 10 cm, find
(a) ∠BAO = 25° (a) sudut q,
Panjang AB = 2(6.5 kos 25°) the angle q,
= 11.78 cm (b) isi padu bahagian yang boleh dimakan.
the volume of the area that can be eaten.
Panjang lengkok KBAT Menilai
= 130° × 2π(6.5) (a) OC(q) = 16 ..............a Format SPM Terbaharu
360° (OC + 2)q = 20
= 14.75 cm OC(q) + 2q = 20 ..............b
Perimeter b – a: 2q = 20 – 16
= 2(11.78) + 2(14.75) q = 2 rad
= 53.06 cm (b) OC = 16 = 8 cm
(b) Luas rantau berlorek 2 1
2
1
= 2 [ 130° × π(6.5) – (6.5) sin 130° ] Isi padu = (8) (2) × 10
2
2
2
360°
2
= 640 cm

3
= 63.5 cm
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2
Soalan Berformat SPM
Kertas 1/Paper 1

1. Rajah menunjukkan sebuah bulatan berpusat O dengan jejari 5 cm. Diberi OQTC ialah C
sebuah segi empat tepat dengan luas 40 cm , cari T
2
The diagram shows a circle with centre O and radius 5 cm. Given OQTC is a rectangle with an B
area of 40 cm , find θ
2
(a) nilai q, dalam radian, (b) luas sektor OAB, O A Q
the value of q, in radians, the area of the sector OAB.
(c) perimeter kawasan berlorek.
the perimeter of the shaded region. KBAT Menilai
[4 markah/marks]
)
(a) OC × CT = 40 (c) Panjang lengkok AB = 5 ( π – 1.01 = 2.81 cm
5 × CT = 40 2
º CT = 8 cm Panjang BT = ! 8 + 5 – 5 = 4.43 cm
2
2
tan q = 8 Perimeter = 2.81 + 4.43 + 3 + 5 = 15.24 cm
5
q = 58° × π = 1.01 rad
180°
(
1
(b) Luas sektor OAB = (5) 2 π – 1.01 )
2 2
= 7.01 cm 2
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