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MODUL • Fizik TINGKATAN 5

1. Kedalaman air, d, di atas permukaan perspek, diukur dengan menggunakan pembaris 15 cm.
The depth of water, d, over a perspex plate, is measured by using a 15 cm ruler.
2. Bekalan kuasa dihidupkan untuk menggetarkan motor supaya gelombang satah merambat merentasi plat
perspek. Gelombang itu dibekukan dengan menggunakan stroboskop mekanikal. Gelombang itu dilakar
pada skrin. / The power supply is switched on to produce plane waves which propagate across the perspex plate.
The waves are frozen by a mechanical stroboscope. The waves are sketched on the screen.
Prosedur 3. Jarak antara 11 jalur terang berturutan, x, diukur dengan menggunakan pembaris meter dan direkodkan
Procedure The distance between 11 successive bright bands, x, is measured by the metre ruler and recorded.
x
4. Panjang gelombang, λ, dikira / The wavelength λ, is calculated, λ = cm
10
5. Eksperimen diulang 4 kali dengan menambahkan bilangan plat perspek untuk mengubah kedalaman air di
atas plat perspek. / The experiment is repeated 4 times by increasing the number of perspex plates to change
the depth of the water across the plate.
UNIT 1
Menjadualkan Kedalaman air / Depth of water, d / cm
data
Tabulation of data Panjang gelombang / Wavelength, λ / cm

Panjang gelombang
Wavelength
λ / cm

Menganalisis data
Analysis of the data
Kedalaman air
Depth of water
0
d / cm

Latihan / Exercise

1 Rajah menunjukkan gelombang satah air bergerak dari kawasan P ke kawasan Q yang mempunyai kedalaman berbeza.
The diagram shows a plane water wave moving from one area P to another area Q of different depths.
P Q
KBAT
Halaju gelombang air di kawasan P ialah 18 cm s . Berapakah halaju
–1
gelombang air di kawasan Q?
The speed of the water wave in area P is 18 cm s . What is the speed of the water
–1
wave in area Q?
12 cm 12 cm
Penyelesaian / Solution
P Q Frekuensi gelombang di kawasan Q adalah bersamaan dengan
frekuensi gelombang di kawasan P.
Frequency of wave in region Q is the same as the frequency of wave in
region P.

8λ = 12 cm Oleh itu, / Hence, v = f λ
4λ = 12 cm 8λ = 12 cm Q Q Q
λ = 12 cm v = (6 Hz) × 1.5 cm
Q
Kedalaman P: / Deep region P: Q 8 = 9.0 cm s –1
4λ = 12 cm v = f λ = 1.5 cm
p
p
p
12 18 cm s = f (3 cm)
–1
λ = 4 cm
p
\ f = 6 Hz
λ = 3 cm
p
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