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Solving Problems Involving Electrical Energy and Power in Daily Life


           Example         1
                                                                                   LET’S ANSWER
                                                                                   LET’S ANSWER
            Figure 3.35 shows a circuit that is supplied with        6 V
            a 6 V battery to light up a lamp. If the current
            is 0.7 A, what is the amount of electrical energy
            used to light up the lamp for one minute?

              Solution                                           Figure 3.35         https://bit.
                                                                                     ly/3jlXjWq

            Step 1:            Step 2:            Step 3:            Step 4:
            Identify the       Identify the       Identify the formula   Solve the problem
            problem            information given  that can be used   numerically


            1 Total electrical energy, E                  3 E = VQ
                                                             Q = It
            2 Potential difference, V = 6 V                  Therefore, E = VIt
               Current, I = 0.7 A
               Time, t = 1 × 60 s                         4 E = 6 × 0.7 × 60

                                                               = 252 J
              KEMENTERIAN PENDIDIKAN MALAYSIA
                      = 60 s




           Example         2                                                             Info
                                                                       Scan the QR code for tips on
            A fluorescent lamp is labelled 240 V, 32 W.                how to use formulae to solve
            Calculate:                                                 problems involving electrical
            (a)  the lamp resistance                                   energy and  power.
            (b) the current flowing through the lamp under
                normal conditions                                                https://bit.
            (c)  the electrical energy that is supplied for three hours in kJ    ly/3lxmt6G

              Solution

             (a)  Electrical power       (b) Electrical power       (c)  Electrical power
                required, P = 32 W          required, P = 32 W          required, P = 32 W
                Potential difference across   Potential difference across   Time, t = 3 × 60 × 60
                the lamp, V = 240 V         the lamp, V = 240 V                = 10 800 s
                Resistance, R =  V  2       Current, I =   P            Electrical energy,
                               P                        V               E = Pt
                             =  240  2               =   32               = 32 × 10 800
                                32                      240
                                = 1 800 W            = 0.13 A             = 345 600 J
                                                                          = 345.6 kJ


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