Page 131 - 30105-2003 การวิเคราะห์วงจรอิเล็กทรอนิกส์ความถี่สูง

123

3.

( R R ) RR
Q = P = P (3.5a)
L
ω L P ( R + R P ) Lω P

, Q 9 & + %ก ) 3 / &

!
R

L
L

Ω
Ω
"#
3.4 ก + 3.4 R = 6.28 , L = 100 mH, Q = 100, R = 1 k ; + %! 9 Q
S S S L
R 2
- ,
ก !ก (3.5) R = P , R = Q R S ;
P
S
Q 2
R = Q R = ) 6.28 62.8 k= Ω
2
2
P S (100

ก Q > "
L =
10
L
P
S
S
L = L = 100 mH
S
P
ω L
ก !ก (3.3) Q = S
S
R S
Q R
ω = S S
L S
×
Q R 100 6.28
F = S S = = 1,000 Hz
π
×
×
×
2 L S 2 3.14 100 10 − 3
( R R ) RR
ก !ก (3.5a) Q = P = P
L
ω L P ω L P ( R + R P )
3
×
1 10 × 62.8 10 3
×
)
Q = ( 2 3.14 1,000 100 10 − 3 )( 1 10 + 62.8 10
L
×
×
×
3
3
×
×
×
Q = 1.567
L
" Q = == = 1.567
L

3.3 . * $

'

(
ก &
.'!( & +;

ก 0 ก.' (Flux Linkage) < (&
, +D!3 !( ! ! 00> ก %
<9
% ! 8+ %! 9 ก !ก

µ
2
L = C N (3.6)
, C 9 (& &
µ 9 !. .#! (Permeability) !9
?ก 00>
N

&

(T)
ก

ก
ก