Page 133 - 30105-2003 การวิเคราะห์วงจรอิเล็กทรอนิกส์ความถี่สูง

125

3.

!ก (3.8)
!ก (3.9)

E P E S
N P = N S
I N P I N S
S
P
E 1 E 1
P × = S ×
N P I N P N S I N S
P
S
E E
P = S
2 2
I N I N
P P S S

ก 9 (!/
.'
& +D!3 !( (Z 9 ก E P % (!/
.'
& )& 3 !(
9
9
(
)
P
I P
(Z 9 ก E S
S )
I S
Z P = Z S , Z = Z N 2 P ; (3.10)
S
P
N 2 P N 2 S N 2 S
"#
3.5 ก + 3.5 E = 100 V, N = 100 T, N = 20 T % Z = 100 Ω + %! 9
P P S S
, E I . Z
ก. E I % I . E I S S ; P
,
P P
P
S
S
, I % I
- ,
ก. E S S P
ก !ก (3.8) E P = E S
N P N S
×
E N 100 20
E = P S = = 20 V
S
N 100
P
E S 20
I = = = 0.2 A
S
Z S 100
ก !ก (3.9) I N = I N
S
S
P
P
×
I N 0.2 20
I = S S = = 40 mA
P
N P 100
" E = == = 20 V, I = == = 0.2 A, I = == = 40 mA;
S
P
S
. E I , E I
;
P P S S
E I = 100 0.04 = 4 VA
×
P P
×
E I = 20 0.2 = 4 VA
S S
" E I = == = E I = == = 4 VA
S S
P P
ก

ก
ก