Page 185 - 30105-2003 การวิเคราะห์วงจรอิเล็กทรอนิกส์ความถี่สูง
P. 185
177
4.
C B
R FLCB r bb′
r b e ′ R ≈ R EP ≈ R EP 1
E
E
g
β +
( o ) 1 R E
1 4.9 . % ก (
R
FLCB
! ก R ≈ R EP ≈ R
E
1
EP
) }
r
R FLCB = R + R BB { bb′ + r b e ′ + ( β + 1 R E
o
g
) }
R BB { bb′ + r b e ′ + (β + 1 R E
r
o
R FLCB = R + ) }
g
R
o
{ BB + r bb′ + r b e ′ + ( β + 1 R E
X C = R FLCB
B
1
! ก X =
C B
π
C
2 F ( L C B ) B
1
R =
FLCB
π
2 F ( L C B ) B
C
1 (4.18)
% & F =
( L C B ) 2 Rπ FLCB B
C
*& 4.14 ก 1 4.5 .5( 4.9 (
F
( L C B )
1
+ , ก
ก (4.18) F =
( L C B )
π
C
2 R FLCB B
) }
r
R BB { bb′ + r b e ′ + (β + 1 R E
o
$% R FLCB = R + ) }
g
R
{ BB + r bb′ + r b e ′ + ( β + 1 R E
o
×
8.432 10 3 {2 461.981+ + (101 560× )}
R FLCB = 75 + = 7.420 kΩ
{ 8.432 10 + 2 461.981+ (101 560× )}
3
+
×
C = 470 pF
B
1
=
F ( L C B ) 2 3.14 7.420 10 × 470 10 − 12
×
×
×
×
3
F = 45.660 kHz
( L C B )
* F = == = 45.660 kHz
( L C B )
ก
ก
ก

