Page 181 - 30105-2003 การวิเคราะห์วงจรอิเล็กทรอนิกส์ความถี่สูง

173
4.

×
(k T q ) 1.38 10 − 23 × (273 25+ )
B
$% r d = = = 4.762 kΩ
×
×
2
I D 2 1.60 10 − 19 × 5.397 10 − 6
I ( ) 5.563 10 − 3
×
g = C dc = = 216.459 mS
m
(k T q ) 25.7 10 − 3
×
B
β o 100
r b e ′ = = − = 461.981 Ω
×
g m 216.459 10 3
×
×
3
R R 2 13 10 × 24 10 3 8.432 kΩ
B
1 B
R BB = = =
×
( R B 1 + R B 2 ) ( 13 10 + 24 10 3 )
3
×
(
3
×
×
r
R E ( d + R L ) 560 4.762 10 + 56 10 3 )
R EP = 2 = = 554.886 Ω
( R + r d 2 + R L ) ( 560 4.762 10 + 56 10 3 )
3
+
×
×
E
R i (0- ) = r bb′ + r b e ′ + ( β + ) 1 R EP
π
F
+
R = 2 461.981+ (101 554.886× )
π
i (0- )
R = 56.507 kΩ
π
i (0- )
R R (0- )
π
BB i
ก
ก (4.11b) R =
π
in (0- )
( R BB + R i (0- ) )
π
$% R = 56.507 kΩ
π
i (0- )
3
×
×
R
R BB i (0- ) 8.432 10 × 56.507 10 3
π
R = = = 7.337 kΩ
π
in (0- ) 3 3 )
( R BB + R i (0- ) ) ( 8.432 10× + 56.507 10
×
π
Ω
Ω Ω Ω
Ω Ω Ω
Ω
* R i (0- ) = = = = 56.507 k , R in (0- ) = = = = 7.337 k ;
π ππ
π ππ
π
π
I ! ก (. 4==D 4
5; D , (0- )# D % # R
π
2
2
d
2
1
! 0 #
5( & 4%

I R
e E
I =
d 2 )
( R + r d 2 + R L
E
*
! ก / 0
β 1 .5( # . % # ก (. I
0
o
b
5( & 4% (4%
I =
e I c
I R
c E
I d =
2
( R + r d 2 + R L )
E
. g V 5 I
m b e ′
c
g V R
′
m b e E
I =
d 2 )
( R + r d 2 + R L
E
ก

ก
ก