Page 251 - 30105-2003 การวิเคราะห์วงจรอิเล็กทรอนิกส์ความถี่สูง
P. 251
243
6.
( 942 10 6 ) ( 269.261 10 − 9 × 342.442 10 − 12 + 1
2
×
×
×
)
L m (new ) = 2
×
×
342.442 10 − 12 ( 942 10 6 )
L = 272.551 nH
m (new )
L = L = 272.551 nH
m 2 m (new )
Ω
Ω Ω Ω
Ω Ω Ω
Ω
R m 1 = = = = 3.18 , L m 2 = = = = 272.551 nH, C m 3 = = = = 4.451 pF, C m 4 = = = = 67.401 pF, R m 5 = = = = 75 ,
C = == = 342.442 pF;
x
Z out = 75 Ω C m 3 L m 2 Z = (3.18 J− 3.10 ) Ω
in
R m 5 R m 1
C
E S m 4
C x
# 4' 6.17 ก ! ;2 (6; !ก : ! 4' 3 ( ! # 2
6.2
ก
0!
$
"
2
ก S 4 24 (Butterworth Low-pass Filters 4
4' ก -
)
−
4' !'" !7' ก " !7' # ( 3 dB) S ก # 4' 6.18 ( ก ( L C
( C !'" ' ก
2 " !7' # 4 6
" !7' # 3
ก 23 ก L !'"
' ก
2 " !7' 4 6
" !7' 3
S L R 3 ก" ! R "
L L
6 4' 6.1 5 " 4'(
" 6; !ก 6 ก ' ( " 'ก" %
E S
:
# 4' 6.18 ก S 4 2 24 ก 2 31
R L
L = L n (6.28)
π
2 F H
C
C = n (6.29)
π
2 F R L
H
ก
ก
ก

