Page 254 - 30105-2003 การวิเคราะห์วงจรอิเล็กทรอนิกส์ความถี่สูง

246
6.

4' 6.3 " 4'(
ก S # 4 2 24

2
ก S # 4 24 (R = 1 )
Ω
L
π R S L 1 n C n 2 L n 3 C n 4 L n 5 C n 6 L n 7 C n 8
n = 2 0.7071 0.7071 - - - - - -
−
( 90) 1
n = 3 1 1.0 0.5 1.0 - - - - -
n = 4 1.3065 0.5411 0.5411 1.3065 - - - -
−
( 180) 1
n = 5 1 1.6181 0.6180 0.5 0.6180 1.6181 - - -

n = 6 1 1.9319 0.7071 0.5176 0.5176 0.7071 1.9319 - -
7 2.2471 0.8019 0.5549 0.5 0.5549 0.8019 2.2471 -
n = 1
8 2.5627 0.9000 0.6013 0.5097 0.5097 0.6013 0.9000 2.5627
n = 1
−
* " L C
R = 1 Ω " " !7' ( 3 dB ก 48)
n
n
L

2

! 6.8 ก # 4' 6.21 ก ก S # 4 24 : ก 2 31
Ω
( $ ก n = 4, R = 50 , R = 50 Ω F = 8 MHz
L
S
L
"# $ ก 4' 6.3 !$ $ ก n = 3 " ! 4' 6.4
4
R S 50 Ω C 2 C 4

E R L 50 Ω
S L 1 L 3

2

# 4' 6.21 ก S # 4 24 n =
4
4' 6.4 " & !$ $ ก n = : ก 2 31
4

π R S L 1 n C n 2 L n 3 C n 4 L n 5 C n 6 L n 7 C n 8

n = 4 1.3065 0.5411 0.5411 1.3065 - - - -
−
( 180) 1

$
ก 4' 6.3
6.4 3 "

L = 1.3065, C n 2 = 0.5411, L n 3 = 0.5411, C n 4 = 1.3065;
1 n
ก

ก
ก