Page 255 - 30105-2003 การวิเคราะห์วงจรอิเล็กทรอนิกส์ความถี่สูง

247
6.

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"

R L
ก !ก (6.28) L = L n
π
2 F H
Ω
(ก
L = L 1 , L = L 1 n , R = 50 , F = F = 8 MHz;
H
L
L
n
×
R L 50 1.3065
L = L 1 n = = 1.30 µH
1
π
2 F × × × 6
L 2 3.14 8 10
×
R L 50 0.5411
L = L n 3 = = 0.538 µH
3 6
π
×
×
×
2 F L 2 3.14 8 10
C
ก !ก (6.29) C = n
π
2 F R
H L
(ก
C = C 2 , C = C n 2 , R = 50 , F = F = 8 MHz;
Ω
L
L
n
H
C 0.5411
C = n 2 = = 215.406 pF
2 6
π
×
×
×
2 F R 2 3.14 8 10 × 50
L L
C 1.3065
C = n 4 = = 520.103 pF
4
π
6
× ×
×
2 F R 2 3.14 8 10 × 50
L L

L = == = 1.30 µH, C = == = 215.406 pF, L = == = 0.538 µH, C = == = 520.103 pF, F = == = 8 MHz;
1 2 3 4 L
2
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